$f(x)=4x-3\\
y=4x-3\\
4x=y+3\\
x=\frac{1}{4}y+\frac{3}{4}\\
f^{-1}(x)=\frac{1}{4}x+\frac{3}{4}\\\\
f^{-1} \circ f=\frac{1}{4}(4x-3)+\frac{3}{4}\\
f^{-1} \circ f=\frac{4x}{4}-\frac{3}{4}+\frac{3}{4}\\
f^{-1} \circ f=x$

4 0

4 years ago

Read 2 more answers

Clark gives 3/10 of his allowance to charity. (<<<

Sunny_sXe [5.5K]

The answer would be 30% , 3% would only be correct if he gave 0.3/10

6 0

3 years ago

Read 2 more answers

I need math people, please

frosja888 [35]

Answer:

it's 60 dollars if I'm wrong in sorry

6 0

3 years ago

Read 2 more answers