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zubka84 [21]
2 years ago
10

Find the LCD for the list of rational expressions. 2 7x +4 x2 + 5x - 14' x2 + 3x – 28

Mathematics
1 answer:
andre [41]2 years ago
7 0

the equation is made and the included values are indicated.

You might be interested in
Find the value of x.<br> (7x - 3)
Musya8 [376]

Answer:

Infinity Many

Step-by-step explanation:

x can pretty much be any number possible. It will just equal something different every time.

8 0
3 years ago
How many different rectangles can you draw, that has an area of 28 cm sq. ? pls help me
jolli1 [7]

Answer:

You can draw three rectangles:

1- 28 * 1.

2- 14*2

3- 7*4

Step-by-step explanation:

We have a total area of 28. If we use only integer numbers, we can find all the divisors of 28. The possible rectangles will be organized with them, taking into account that the product of them, which means the area should be 28.

28 = 1*2*2*7

We can organize them as follows:

R1: 28 = 1*28

R2: 28 = 2*14

R3: 28 = 4*7

Finally, we can conclude that there are only three possibilities

1- 28 by 1.

2- 14 by 2

3- 7 by4

The perimeters will be:

Perimeter 1 = 2x1 + 2x28 = 58

Perimeter 2 = 2x2 + 2x14 = 32

Perimeter 3 = 2x4+2x7 = 22

3 0
3 years ago
The mean percentange of a population of people eating out at least once a week is 57℅
Sidana [21]

Answer:

<u>The correct answer is B. between 56.45% and 57.55% </u>

Complete statement and question:

The mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.50%. Assume that a sample size of 40 people was surveyed from the population a significant number of times. In which interval will 68% of the sample means occur?

between 55.89% and 58.11%

between 56.45% and 57.55%

between 56.54% and 57.46%

between 56.07% and 57.93%

Source: brainly.com/question/1068489

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean percentage of a population of people eating out at least once a week  = 57%

Standard deviation = 3.5%

Sample size = 40

Confidence level = 68%

2. In which interval will 68% of the sample means occur?

For answering this question, we should find out the standard deviation of the sample, using this formula:

Standard deviation of the sample = Standard deviation of the population/√Sample size

Standard deviation of the sample = 3.5/√40

Standard deviation of the sample = 3.5/6.32

Standard deviation of the sample = 0.55

Let's recall that a confidence level of 68% means that 68% of the sample data would have a value between the mean - 1 time the standard deviation of the sample and the mean  + 1 time the standard deviation of the sample. Thus:

57 - 1 * 0.55 = 57 - 0.55 = 56.45

57 + 1  * 0.55 = 57 + 0.55 = 57.55

<u>The correct answer is B. between 56.45% and 57.55% </u>

7 0
3 years ago
Ernesto is shopping at store that is having a clearance sale. The price of everything in the store is discounted by 25%. If Earn
maksim [4K]
$17.49 because you multiply 22 by .25 getting 5.5. You subtract that from the original 22 getting 16.5 which you then multiply by the sales tax .06. Add the tax amount to the 16.5 to get 17.49.
3 0
3 years ago
How do I solve
Maslowich

Use:\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^n\cdot a^m=a^{n+m}\\\\\sqrt[n]{a}=a^\frac{1}{n}\\------------------------\\\\\left(16n^4\right)^{\frac{5}{4}}=16^\frac{5}{4}\left(n^4\right)^\frac{5}{4}=16^{1\frac{1}{4}}n^{4\cdot\frac{5}{4}}=16^{1+\frac{1}{4}}n^5=16^1\cdot16^\frac{1}{4}\cdot n^5\\\\=16\cdot\sqrt[4]{16}\cdot n^5=16\cdot2\cdot n^5=\boxed{32n^5}\\\\\sqrt[4]{16}=2\ because\ 2^4=16\\\\\text{Answer}\ \boxed{\left(16n^4\right)^\frac{5}{4}=32n^5}

4 0
3 years ago
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