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nekit [7.7K]
3 years ago
11

Which number line best shows how to solve −4 − (−6)? (5 points)

Mathematics
1 answer:
kiruha [24]3 years ago
6 0

Answer:

the last one

Step-by-step explanation:

-4 - (-6) is actually -4 + 6, which equals 2

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The amount of roses given out would be 300 roses in total.
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The values of a, b, and c in the equation x² + 6x - 55 = 0 are:
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The following are the answers:

a = 1

b = 6

c = -55

Step-by-step explanation:

When looking for a, b, and c in a quadratic, you are looking at coefficients only. The coefficient of x^2, which in this case is 1, is a. The coefficient of x, which in this case is 6, is b. Lastly, the constant at the end, which in this case is -55, is c.

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4 years ago
A blood sample with a known glucose concentration of 102.0 mg/dL is used to test a new at home glucose monitor. The device is us
Soloha48 [4]

Answer:

The Absolute Error is the difference between the actual and measured value.

Absolute \:error = |Actual \:value - Measured \:value|

The Relative Error is the Absolute Error divided by the actual measurement.

Relative \:error = \frac{Absolute \:error}{Actual \:value}

We know that the actual value is 102.0 mg/dL.

To find the absolute error and relative error for each measurement made by the glucose monitor you must use the above definitions.

a) For a concentration of 104.5 mg/dL the absolute error and relative error are

Absolute \:error = \left|102-104.5\right|\\Absolute \:error =\left|-2.5\right|\\Absolute \:error =2.5

Relative \:error = \frac{2.5}{102.0}=0.0245

b) For a concentration of 96.2 mg/dL the absolute error and relative error are

Absolute \:error = \left|102.0-96.2\right|\\Absolute \:error =\left|5.8\right|\\Absolute \:error =5.8

Relative \:error = \frac{5.8}{102.0}=0.0569

c) For a concentration of 102.2 mg/dL the absolute error and relative error are

Absolute \:error = \left|102.0-102.2\right|\\Absolute \:error =\left|-0.2\right|\\Absolute \:error =0.2

Relative \:error = \frac{0.2}{102.0}=0.00196

d) For a concentration of 98.3 mg/dL the absolute error and relative error are

Absolute \:error = \left|102.0-98.3\right|\\Absolute \:error =\left|3.7\right|\\Absolute \:error =3.7

Relative \:error = \frac{3.7}{102.0}=0.0363

e) For a concentration of 101.8 mg/dL the absolute error and relative error are

Absolute \:error = \left|102.0-101.8\right|\\Absolute \:error =\left|0.2\right|\\Absolute \:error =0.2

Relative \:error = \frac{0.2}{102.0}=0.00196

4 0
3 years ago
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