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aalyn [17]
3 years ago
14

Keiko uses 6.9 pints of blue paint and white paint to paint her bedroom walls. 2/5 of this amount is blue paint, and the rest is

white paint. How many pints of white paint did she use to paint her bedroom walls?
Mathematics
1 answer:
lianna [129]3 years ago
5 0

Answer: 4.14\ \text{pints}

Step-by-step explanation:

Given

Keiko uses 6.9 Pints of blue and white paint

If the fraction of blue paint is \frac{2}{5}, then thr fraction of white paint is

1-\dfrac{2}{5}=\dfrac{3}{5}

Amount of white paint is

\Rightarrow \dfrac{3}{5}\times 6.9=4.14\ \text{pints}

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babymother [125]

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4 0
2 years ago
you are assembling desserts with a friend together you can make 12 desserts in 5 minutes. how many can you make in 20 minutes?
Sever21 [200]
You can solve this in two ways.

First way:
Let’s find out how many my friend makes in one minute.
12/5=2.4
He makes 2.4 in one minute. Let’s multiply that by 20 to find what he makes in 20 minutes.
2.4•20=48
My friend made 48 desserts.

Second way:
Let’s make a ratio.
12 desserts:5 minutes
X desserts: 20 minutes
Whatever you do to one side, you have to do to the other. Since you are multiplying the minutes by 4, you have to multiply the desserts by 4.
12•4=48

So, my friend made 48 desserts.
Tell me if this helps!!!
3 0
3 years ago
Estimate the quotient: 1628 ÷ 8
Pachacha [2.7K]

Answer:

203.5

Step-by-step explanation:

Please mark brainliest.

4 0
3 years ago
Read 2 more answers
Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va
Burka [1]

Answer:

\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}

The polynomial is an approximation with an error less than or equals to <em>0.002652</em> for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)

with

\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}

for some c in the interval (-x, x)

In the particular case f

<em>f(x)=cos(x) </em>

<em> </em>

we have

\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)

therefore

\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0

and the polynomial approximation of T5(x) of cos(x) would be

\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}

for some c in (-x,x). So

\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}

and we must find the values of x for which

\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652

Working this inequality out, we find

\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0
3 years ago
when (2x - 3)^2 is subtracted from 5x^2, what is the result? And how can I show the answer? Thank you x
Leni [432]
5x^2 - (2x - 3)^2 = 
5x^2 - ((2x - 3)(2x - 3)) =
5x^2 - (4x^2 - 6x - 6x + 9) =
5x^2 - (4x^2 - 12x + 9) =
5x^2 - 4x^2 + 12x - 9 =
x^2 + 12x - 9 <===
3 0
4 years ago
Read 2 more answers
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