Answer:
B
Step-by-step explanation:
7pi2
The probability of getting 3 or more who were involved in a car accident last year is 0.126.
Given 9% of the drivers were involved in a car accident last year.
We have to find the probability of getting 3 or more who were involved in a car accident last year if 14 were selected randomly.
We have to use binomial theorem which is as under:
n
where p is the probability an r is the number of trials.
Probability that 3 or more involved in a car accident last year if 14 are randomly selected=1-[P(X=0)+P(X=1)+P(X=2)]
=1-{
}
=1-{1*0.2670+14!/13!*0.9*0.29+14!/2!12!*0.0081*0.2358}
=1-{0.2670+0.3654+0.2358}
=1-0.8682
=0.1318
Among the options given the nearest is 0.126.
Hence the probability that 3 or more are involved in the accident is 0.126.
Learn more about probability at brainly.com/question/24756209
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Answer:
x = 12
Step-by-step explanation:
6x - 4 and 112 are same- side interior angles and sum to 180° , that is
6x - 4 + 112 = 180
6x + 108 = 180 ( subtract 108 from both sides )
6x = 72 ( divide both sides by 6 )
x = 12
Answer:
x=4
Step-by-step explanation:
3/4(x+8)=9
simplify
3/4x+6=9
-6 -6
3/4x=3
multiply 4
3x=12
divide 3
x=4
6/10+7/12
=72/120+70/120
=142/120
=120/120+22/120
=1+22/120
=1+11/60
<em>*Good estimate would be 1+1/6 = 1.17</em>