All categories

3 years ago

How to graph the second equation

Mathematics

1 answer:

Iteru [2.4K]3 years ago

3 0

X - y = -8
3x + 7y = -14

now make the y the subject

- y = - x - 8
7y = - 3x - 14

work on both equations
make the x = 0

-y = -(0) -8
-y = - 8
-y / -1 = -8 / -1
y = 8

and make the y = 0

-y = -x - 8
-(0) = -x - 8

-y = -8
-y / -1= -8/-1
y = 8
( 8 , -8)

and other equation i given to you to do it and your graph should be negative

You might be interested in

Choose the student who wrote the correct inequality.

svp [43]

Answer:

Tori

Step-by-step explanation:

if youre making over 90 percent of your free throws, then any number (P) greater than 90 is the answer

7 0

3 years ago

Read 2 more answers

The average value of two positive numbers is 30% less than one of the two numbers. By which percentage is average value bigger t

Viefleur [7K]

Answer:

75% bigger

Step-by-step explanation:

Let the first number be x and the second be y.

So:

$Average = \frac{x + y}{2}$

And:

$Average = (1 - 30\%) * x$ -----30% less than x

Substitute $Average = (1 - 30\%) * x$ in $Average = \frac{x + y}{2}$

$\frac{x + y}{2} = (1 - 30\%) * x$

$\frac{x + y}{2} = (1 - 0.30) * x$

$\frac{x + y}{2} = 0.70 * x$

$\frac{x + y}{2} = 0.70x$

Cross multiply

$x + y = 0.70x * 2$

$x + y = 1.40x$

Collect like terms

$1.40x - x = y$

$0.40x = y$

Make x the subject

$x = \frac{y}{0.40}$

$x = 2.50y$

So, the average is:

$Average = (1 - 30\%) * x$

$Average = (1 - 30\%) * 2.50y$

$Average =0.70 * 2.50y$

$Average =1.75y$

Rewrite as:

$Average =(1 + 0.75)y$

Express as percentage

$Average =(1 + 75\%)y$

This means that the average is 75% bigger than the second number

6 0

3 years ago

Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
\\\\\\
\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

3 years ago

Find the missing side of the triangle. leave your answer in simplest radical form

KIM [24]

missing side is $x} = 10.15$ mi .

Step-by-step explanation:

Here we have the following info from the figure: A right angled triangle with following dimensions

$Perpendicular = x$

$base = \sqrt{122}$

$Hypotenuse = 15$

By Pythagoras Theorem :

$Hypotenuse^2 = Perpendicular^2 + base^2$

⇒ $Hypotenuse^2 = Perpendicular^2 + base^2$

⇒ $15^2 = x^2 + (\sqrt{122})^2$

⇒ $225 = x^2 + 122$

⇒ $x^2 = 225-122$

⇒ $x^2 = 103$

⇒ $(x^2)^\frac{1}{2} = (103)^\frac{1}{2}$

⇒ $x} = (103)^\frac{1}{2}$

⇒ $x} = 10.15$

Therefore, missing side is $x} = 10.15$ mi .

8 0

3 years ago

The concentration of dichlorodiphenyltrichloroethane (DDT - an infamous pesticide) in Lake Michigan has been declining exponenti

mojhsa [17]

Answer: A) $y=13e^{-0.1359t}$

B) H = 5.10

C) Yes

Step-by-step explanation: Exponential Decay function is a model that describes the reducing of an amount by a constant rate over time. Generally, it is written in the form: $y(t)=Ce^{rt}$