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3 years ago

Find the product of 13 and -31

Mathematics

2 answers:

maria [59]3 years ago

5 0

Answer:

-403

hope it helps.

have a good day

Elanso [62]3 years ago

3 0

Answer:

-403

Step-by-step explanation:

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What is the answer 2(4y+1)=3y

SCORPION-xisa [38]

2(4y+1) = 3y. We need to solve for y.
First let's get ride of the parenthesis by developing 2(4y+1). This means to multiply 2 by 4y and 2 by 1, and add them.
2(4y+1) = 2*4y + 2*1 = 8y + 2
So 2(4y+1)=3y
8y+2 = 3y
Then you subtract 8y from each side to have the variables on a side and the numbers on the other:
3y - 8y = 8y + 2 - 8y
-5y = 2
Then you divide each side by -5 to get the variable y alone on a side and its value on the other:
(-5y)/-5 = 2/-5
y = -2/5

You can re-check your answer (very important):
2(4y + 1) = 2(4*-2/5 + 1) = -1.2
3y = 3 * -2/5 = -1.2
So 2(4y+1)=3y= -1.2
The answer has been approved.

Hope this Helps! :)

4 0

4 years ago

When it is easier to use the point-slope form to write the equation of a line and when it is easier to use the slope-intercept f

Pani-rosa [81]

Point slope form is used when we have the information of at least two coordinates that lie on the line

For example:

Given that coordinate (3, 4) and (6, 7) lies on a straight line.

We work out the equation of the line by substituting the two coordinates into the formula (y - y₁) = m(x - x₁) where (x₁, y₁) could be either (3, 4) and (6, 7).

We would need to use both coordinates to work out the gradient (m) by using the formula:
$m= \frac{vertical distance}{horizontal distance} = \frac{y_2-y_1}{x_2-x_1}$
----------------------------------------------------------------------------------------------------------------

The slope intercept form is used when we are given enough information to work out the gradient as well as the y-intercept.

For example:
Given two coordinates (3, 5) and (0, 9)
This information can help to find the gradient and the y-intercept.
The y-intercept would be at 9 because the (0, 9)
We calculate the gradient m
Then substitute into y=mx+c which is the slope intercept form.

3 0

3 years ago

Help me please. 30 points :)

Nataly [62]

$\frac{(5 \: - \: 8x)}{( \sqrt{5 \: - \: 8x} )} \: = \: \sqrt{5 \: - \: 8x}$
For the result to be Real,
$5 \: - \: 8x \: \geqslant \: 0$
$8x \: \leqslant \: 5$
$x \: \leqslant \: \frac{5}{8}$
$( \frac{(5 - 8x)}{( \sqrt{5 - 8x} )} ) \: \times \: (\frac{ \sqrt{5 - 8x} }{ \sqrt{5 - 8x} } ) \: = \: \frac{ {(5 \: - \: 8x)}^{ \frac{3}{2} } }{(5 \: - \: 8x)}$
Hence,
$\frac{{(5 \: - \: 8x)}^{ \frac{3}{2} } }{(5 \: - \: 8x)}$
is the required form.

3 0

3 years ago

How do you do this question?

Gemiola [76]

Answer:

-30√(t/a) cos(√(at)) + 30/a sin(√(at)) + C

Step-by-step explanation:

∫ 15 sin(√(at)) dt

Use substitution:

If x = √(at), then:

dx = ½ (at)^-½ (a dt)

dx = a / (2√(at)) dt

dx = a/(2x) dt

dt = (2/a) x dx

Plugging in:

∫ 15 sin x (2/a) x dx

30/a ∫ x sin x dx

Integrate by parts:

If u = x, then du = dx.

If dv = sin x dx, then v = -cos x.

∫ u dv = uv − ∫ v du

= 30/a (-x cos x − ∫ -cos x dx)

= 30/a (-x cos x + ∫ cos x dx)

= 30/a (-x cos x + sin x + C)

Substitute back:

30/a (-√(at) cos(√(at)) + sin(√(at)) + C)

-30√(t/a) cos(√(at)) + 30/a sin(√(at)) + C

5 0

3 years ago

The product of two numbers is a ______ of both numbers

qwelly [4]

<h2>The product of two numbers is <em>a,</em> $\sqrt{a}$ of both numbers.</h2>

Step-by-step explanation:

Given,

The product of two numbers = a

To find, the both numbers = ?

Let the two numbers = x

∴ x × x = a

⇒ $x^{2}$ = a

⇒ $x^{2} =\sqrt{a}^2$

Comparing the powers, we get

⇒ x = $\sqrt{a}$

∴ First number = $\sqrt{a}$ and Second number = $\sqrt{a}$

Thus, the product of two numbers is <em>a,</em> $\sqrt{a}$ of both numbers.

5 0

3 years ago

Find the product of 13 and -31​

Find the product of 13 and -31