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Elden [556K]
3 years ago
13

If the Volume of a Cone is 37.68inº and height is 9in, what is the diameter?

Mathematics
1 answer:
shtirl [24]3 years ago
4 0

Answer:

37.68inº

Step-by-step explanation:

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The radius of a circle is 4 m. Find its area in terms of <br> π<br> π.
wlad13 [49]

Answer:

16π

Step-by-step explanation:

Given:

\text{Radius of circle}: 4 \ \text{m}

<u>Formula:</u>

\text{Area of circle} = \pi r^{2}

Replace the radius in the formula:

\implies \text{Area of circle} = \pi (4)^{2}

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Read 2 more answers
Given: PRST is a square
xxTIMURxx [149]

Answer:

(1-\sqrt{2})a^2

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a

Thus,

MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a

Consider isosceles triangle MSC. In this triangle

MS=MC=(\sqrt{2}-1)a.

The area of this triangle is

A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}

Consider right triangle PTS. The area of this triangle is

A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2

5 0
3 years ago
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