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3 years ago

If the Volume of a Cone is 37.68inº and height is 9in, what is the diameter?

Mathematics

1 answer:

shtirl [24]3 years ago

4 0

Answer:

37.68inº

Step-by-step explanation:

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How to do multiplicities

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3 years ago

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Vladimir79 [104]

Answer:

A. 8

Step-by-step explanation:

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3 years ago

The radius of a circle is 4 m. Find its area in terms of <br> π<br> π.

wlad13 [49]

Answer:

16π

Step-by-step explanation:

Given:

$\text{Radius of circle}: 4 \ \text{m}$

<u>Formula:</u>

$\text{Area of circle} = \pi r^{2}$

Replace the radius in the formula:

$\implies \text{Area of circle} = \pi (4)^{2}$

Evaluate the area:

$\implies \text{Area of circle} = \pi (4)(4)$

$\implies \text{Area of circle} = 16\pi$

Since the question says to determine the area in terms of π, the final answer is 16π.

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2 years ago

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3 years ago

Read 2 more answers

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

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3 years ago