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notsponge [240]
3 years ago
12

Un gusano está subiendo un postre que mide 2 metros de largo, en su ascenso, descansa cada 3 cm, pero por cada 3cm que avanza, r

esbala 1cm.
cual es la cantidad de descansos que tendra que hacer para llegar a la sima del poste
Mathematics
1 answer:
kupik [55]3 years ago
6 0
600/800 descansos porque mencionaste que se toma un descanso cada 3 cm pero se desliza 1 cm cada vez que se toma un descanso, así que solo cambia los 2 ma cm, que es 200 veces eso a 3 o 4 y obtendrás el número de descansos (acabo de adivinar)
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Roman55 [17]

Answer:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

Step-by-step explanation:

Given system of equations:

\begin{cases}y=x^2-9\\y=4x-4\end{cases}

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}

Factor the quadratic:

\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}

Apply the <u>zero-product property</u> and solve for x:

\implies x+1=0 \implies x=-1

\implies x-5=0 \implies x=5

Substitute the found values of x into the <u>second equation</u> and solve for y:

\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}

\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}

Therefore, the solutions are:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

6 0
1 year ago
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drek231 [11]

Answer:$21.2

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multiply 19.25*6.25 then divide by 100 then add that answer onto 19.25 to then get an estimate of 21.2 dollars

3 0
3 years ago
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Harlamova29_29 [7]

Answer:

Step-by-step explanation:

a) PR=SU

b) PQ=TU

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5 0
3 years ago
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Between wich two integers is the value of √21
RSB [31]
4 and 5
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3 years ago
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