50%. Might be wrong but all I did was reduce 30% from 80%
Dang...H0: μ = 115
HA: μ ≠ 115
Sample mean = 120
Standard deviation = 25
Standard error of mean = σ / √ n
Standard error of mean = 25 / √ 100
SE = 25/10
Standard error of mean 2.5
z = (xbar- μ ) / SE
z = (120-115) / 2.5
z = 2
p-value = 2 P( z > 2) = 2(0.0228) = 0.0456
the data are statistically significant at level = .05, but not at level = .01.
2)
H0: μ = 115
HA: μ ≠ 115
Sample mean = 119
Standard deviation = 25
Standard error of mean = σ / √ n
Standard error of mean = 25 / √ 100
SE = 25/10
Standard error of mean 2.5
z = (xbar- μ ) / SE
z = (119-115) / 2.5
z = 1.6
p-value = 2P( z > 1.6) = 2(0.0548) =0.1096
3)
a statement about the population the researcher suspects is true, and is trying to find evidence for.
4)
Sample mean = 80
Standard deviation = 20
Standard error of mean = σ / √ n
Standard error of mean = 20 / √ 100
SE = 20/10
The Standard error of mean 2
Confidence interval 80-(2)(1.645)
and 80+(2)(1.645)
(76.7, 83.3)
Answer:
1615
Step-by-step explanation:
Area of triangle is: A= B•H•1/2
Area of square is A= L•W
39•17•1/2= 331.5
331.5•4= 1326
17•17= 289
Add the square area to the area of the triangles
289+ 1326= 1615
hope this helps chu <3
First you bring the 9 over with the seven
![-2= \sqrt[3]{x+9}](https://tex.z-dn.net/?f=-2%3D%20%5Csqrt%5B3%5D%7Bx%2B9%7D%20)
Now cube both sides
Finally subtract 9 over and get
Check
![7=9+ \sqrt[3]{-17+9}](https://tex.z-dn.net/?f=7%3D9%2B%20%5Csqrt%5B3%5D%7B-17%2B9%7D%20)
![7=9+ \sqrt[3]{-8}](https://tex.z-dn.net/?f=7%3D9%2B%20%5Csqrt%5B3%5D%7B-8%7D%20)
7=7
