Before Brian starts messing with them, there are 24 balls in the bag.
9 of them are white.
-- The probability that Brian draws a white ball from the bag is (9/24) .
If he has already drawn one white ball and put it aside, then there are
23 balls left in the bag, and 8 of them are white.
-- The probability that Brian draws a white ball from the bag this time
is (8/23) .
So the probability of white balls on both draws is
(9/24) x (8/23) =
(72/552) =
3 / 23 = about <em>13% </em>(rounded)
Answer:
the ball reaches a height of 64 feet after 2 sec.
The ball is in the air 4 sec.
Step-by-step explanation:
The ball is following the path of a parabola. The maximum height is at the vertex of the parabola.
Let (h, k) be the vertex. h will be the time it takes to reach the maximum height, and k will be that height.
y =
h = -b/2a = 64/(-2)(-16) = 64/32 = 2
k = -16(2)^2 + 64(2)
-16(4) + 128
- 64 + 128 = 64
V: (2, 64)
So the ball reaches a height of 64 feet after 2 sec.
Let = 0 (0 is the height when the balls hits the ground)
-16t(t - 4) = 0
t = 0 or t = 4
The ball is in the air 4 sec.
transverse s at angle 135°
180° - 135° = 45°
Angle 2 is congruent to 45° because they're alternate exterior angles.
transverse t at angle 120°
180° - 120° = 60°
Angle 3 is congruent to 60° because they're alternate exterior angles.
One rule for exterior angles in triangles is that the exterior angle is equal to the sum of the two angles adjacent to the opposite angle of the exterior angle.
135° = angle 1 + 60°
angle 1 = 75°
120° = angle 1 + 45°
angle 1 = 75°
Therefore angle 1 is 75°,angle 2 is 45° and angle 3 is 60°
Answer:
10,597.50 cubic mm
Step-by-step explanation:
V(cone) = [3.14(h)(r²)] ÷ 3
= 3.14(15)(15²) ÷ 3
= 10,597.5