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kipiarov [429]
3 years ago
14

How do you translate "A fifteenth of a number, p." as a variable expression.​

Mathematics
1 answer:
Elden [556K]3 years ago
5 0

Answer:

1/15p?

Step-by-step explanation:

you’re multiplying p by 1/15 if I understood the question right

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Equation of a line that is perpendicular to given line is y=\frac{-7}{4} x+\frac{7}{4}.

Equation of a line that is parallel to given line is y=\frac{4}{7} x-\frac{69}{7}.

Solution:

Given line y=\frac{4}{7} x+4.

Slope of this line, m_1 = \frac{4}{7}

$\text{Slope of perpendicular line} = \frac{-1}{\text{Slope of the given line} }

                                   $m_2=\frac{-1}{m_1}

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Slope of perpendicular line, m_2=\frac{-7}{4}

Passes through the point (–7, 5). Here x_1=-7, y_1=5.

Point-slope formula:

y-y_1=m(x-x_1)

$y-(-7)=\frac{-7}{4} (x-5)

$y+7=\frac{-7}{4} x+\frac{35}{4}

Subtract 7 from both sides, we get

$y=\frac{-7}{4} x+\frac{7}{4}

Equation of a line that is perpendicular to given line is y=\frac{-7}{4} x+\frac{7}{4}.

To find the parallel line:

Slopes of parallel lines are equal.

m_1=m_3

$m_3=\frac{4}{7}

Passes through the point (–7, 5). Here x_1=-7, y_1=5.

Point-slope formula:

$y-(-7)=\frac{4}{7} (x-5)

$y+7=\frac{4}{7} x-\frac{20}{7}

Subtract 7 from both sides,

$y=\frac{4}{7} x-\frac{69}{7}

Equation of a line that is parallel to given line is y=\frac{4}{7} x-\frac{69}{7}.

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