A quadratic function whose vertex is the same as the y-intercept has the equation
y=x^2+k (where k is the y-intercept, with vertex (0,k))
Since the vertex coincides with the y-intercept, the axis of symmetry is x=0.
Hi, sorry i couldn't understand the format of the question, could you post a picture of the question please?
The answer is c to your question
Answer: 0, 4, -9
Set the equation equal to zero.
x(x - 4)(x + 9) = 0
Solve for x by setting each factor equal to zero.
The factors in the equation are x, (x - 4), and (x + 9).
x = 4
x = -9
The zeros of the function are 0, 4, and -9.
Answer:
The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.Step-by-step explanation:
