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adell [148]
4 years ago
14

A ladder is placed 30 inches from a wall. It touches the wall at a height of 50 inches from the ground.

Mathematics
1 answer:
tankabanditka [31]4 years ago
8 0
To find the length of the ladder, you need to do Pythagorean theorem.
50^2 + 30^2 = x^2
2500 + 900 = x^2
x^2 =3400
x= square root of 3400
58.31 OR 10 root34

To find the angle:
tan theta = opposite/adjacent
50/30 = 5/3
theta = tan inverse of 5/3
= 59.04


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Given that f(–2.4) = -1 and f(-1.9) = -8, approximate<br> f'(-2.4).<br> f'(-2.4)
lora16 [44]

Answer:

f'(-2.4) ≈ -14

General Formulas and Concepts:
<u>Algebra I</u>

Coordinate Planes

  • Coordinates (x, y)

Slope Formula: \displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}

Functions

  • Function Notation

<u>Calculus</u>

Differentiation

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  • Derivative Notation

Step-by-step explanation:

*Note:

The definition of a derivative is the slope of the <em>tangent</em> <em>line</em>.

<u>Step 1: Define</u>

<em>Identify.</em>

f(-2.4) = -1

f(-1.9) = -8

<u>Step 2: Differentiate</u>

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>.

  1. [Derivative] Set up [Slope Formula]:                                                           \displaystyle f'(-2.4) \approx \frac{f(x_2) - f(x_1)}{x_2 - x_1}
  2. Substitute in coordinates:                                                                           \displaystyle f'(-2.4) \approx \frac{-8 - -1}{-1.9 - -2.4}
  3. Evaluate:                                                                                                       \displaystyle f'(-2.4) \approx -14

---

Learn more about derivatives: brainly.com/question/17830594

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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3 years ago
In a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Interne
Dvinal [7]

Answer:

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

Step-by-step explanation:

Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.

H_0: \bar x =12.7\\H_a: \bar x >12,7

(Right tailed test at 5% level)

Mean difference = 0.2

Std error = \frac{6}{\sqrt{1000} } \\=0.1897

Z statistic = 1.0540

p value = 0.145941

since p >alpha we do not reject H0.

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

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3 years ago
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Answer:

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Step-by-step explanation:

given

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if k>0, move k units up

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your x- intercept is (-1/7,0)

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When is the absolute value of a difference equal to the difference of the absolute values?
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<span>ax(d) = absolute value of the difference = ax(a-b).
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Hope this works :)</span>
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