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Soloha48 [4]
3 years ago
6

The relation {(-1, 4), (2, 7), (3, 7)} is a function.

Mathematics
1 answer:
scoray [572]3 years ago
4 0
It is a function because the X does not repeat. If the X repeat then it is not function for example.
(2,4), (5,6), (2,8) if it repeat like this then it is not function
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Given f (x) = -3x + 4, solve for x when f (x) = 1
Solnce55 [7]

Answer:

1

Step-by-step explanation:

8 0
2 years ago
Using the distributive property, which number sentence represents the total area of the rectangle?
Daniel [21]

D. is the answer. Your welcome

8 0
3 years ago
For the function​ below, find a formula for the upper sum obtained by dividing the interval [a comma b ][a,b] into n equal subin
Vlad [161]

Answer:

See below

Step-by-step explanation:

We start by dividing the interval [0,4] into n sub-intervals of length 4/n

[0,\displaystyle\frac{4}{n}],[\displaystyle\frac{4}{n},\displaystyle\frac{2*4}{n}],[\displaystyle\frac{2*4}{n},\displaystyle\frac{3*4}{n}],...,[\displaystyle\frac{(n-1)*4}{n},4]

Since f is increasing in the interval [0,4], the upper sum is obtained by evaluating f at the right end of each sub-interval multiplied by 4/n.

Geometrically, these are the areas of the rectangles whose height is f evaluated at the right end of the interval and base 4/n (see picture)

\displaystyle\frac{4}{n}f(\displaystyle\frac{1*4}{n})+\displaystyle\frac{4}{n}f(\displaystyle\frac{2*4}{n})+...+\displaystyle\frac{4}{n}f(\displaystyle\frac{n*4}{n})=\\\\=\displaystyle\frac{4}{n}((\displaystyle\frac{1*4}{n})^2+3+(\displaystyle\frac{2*4}{n})^2+3+...+(\displaystyle\frac{n*4}{n})^2+3)=\\\\\displaystyle\frac{4}{n}((1^2+2^2+...+n^2)\displaystyle\frac{4^2}{n^2}+3n)=\\\\\displaystyle\frac{4^3}{n^3}(1^2+2^2+...+n^2)+12

but  

1^2+2^2+...+n^2=\displaystyle\frac{n(n+1)(2n+1)}{6}

so the upper sum equals

\displaystyle\frac{4^3}{n^3}(1^2+2^2+...+n^2)+12=\displaystyle\frac{4^3}{n^3}\displaystyle\frac{n(n+1)(2n+1)}{6}+12=\\\\\displaystyle\frac{4^3}{6}(2+\displaystyle\frac{3}{n}+\displaystyle\frac{1}{n^2})+12

When n\rightarrow \infty both \displaystyle\frac{3}{n} and \displaystyle\frac{1}{n^2} tend to zero and the upper sum tends to

\displaystyle\frac{4^3}{3}+12=\displaystyle\frac{100}{3}

8 0
3 years ago
Which of the binomials below is a factor of this trinomial ? X^2 -13+42
lapo4ka [179]

In this case we have the following trinomial:

x ^ 2 -13x + 42

By definition, the factorization is a technique that consists in the mathematical decomposition of an expression, in the form of a product. Having said that, we can factor the given trinomial in the following way:

We look for two numbers that when multiplied give as result 42, and when summed give as result -13.

The numbers that meet these two conditions are -6 and -7 by:

-6 * -7 = 42\\-6-7 = -13

So, we have:

(x-6) (x-7)

Answer:

The binomials associated with the given trinomial are(x-6) and (x-7).


4 0
3 years ago
Solve inequalities<br> x+4&gt;-15
Phoenix [80]
X + 4 > -15
- 4
x > -19

So your answer is x > -19, I hope this helps!
6 0
3 years ago
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