Answer:
66 tens - 38 tens= 58 tens
Step-by-step explanation:
You will start off by making the 6 in the ones place a 16 since you can't subtract 6-8 and change the 6 in the tens to a 5 since you borrowed. Hope this helps! :)
<h3>
CloutAnswers</h3>
Answer:
The answer in the procedure
Step-by-step explanation:
we know that
The rule of the reflection of a point over the y-axis is equal to
A(x,y) ----->A'(-x,y)
That means -----> The x-coordinate of the image is equal to the x-coordinate of the pre-image multiplied by -1 and the y-coordinate of both points (pre-image and image) is the same
so
A(3,-1) ------> A'(-3,-1)
The distance from A to the y-axis is equal to the distance from A' to the y-axis (is equidistant)
therefore
To reflect a point over the y-axis
Construct a line from A perpendicular to the y-axis, determine the distance from A to the y-axis along this perpendicular line, find a new point on the other side of the y-axis that is equidistant from the y-axis
Answer: i'd say c
Step-by-step explanation:
Answer:
The answer is 33.
Step-by-step explanation:
4x^2 + 13 - 2y, x=3 y=8
In order to evaluate this, you just need to plug the x and y in the expression:
= 4(3)^2 + 13 - 2(8)
= 4(9) + 13 - 16
= 36 + 13 - 16
= 33
Let the number be 'a':
The difference of the square of a number and 4
a^2 -4
is equal to 3 times that number.
= 3*a
a^2 -4 =3a
a^2 -3a -4=0
(a-4) (a+1)=0
solutions are: 4 and -1