Question

:)))) solve the following by factorizing: x^2-2x=120

Answer 1

Answer:

Step-by-step explanation:

$x^2 - 2x = 120\\x^2 - 2x - 120 = 0$

We have to find the factors of 120 that can either add up to or have a difference of 2.

The factors of 120 are:

$\pm 1, 120, 2, 60, 3, 40, 4, 30, 5, 44, 6, 20, 8, 15, 10, 12...$

The difference of 10 and 12 is 2. In the equation, since the 2 is negative, the larger number must be subtracted, so the factorized form is:

$(x+10)(x-12)$