Answer:
This is what the code should do:
“Lift off in T minus
5
4
3
2
1
Blast-off!”
When I run it, it just keeps printing ''Sum = 5'' forever.
Explanation:
Code:
int main(void) {
int sum = 5;
int i;
printf("Lift off in T minus\n");
for (i = 0; i < 5; i=i+i) {
sum = sum - i;
printf("sum = %d\n",sum);
}
printf("Blast-off",sum);
return 0;
Answer:
Following are the code to this question:
list_val = input()#defining a integer variable for input value
test_grades = list(map(int, list_val.split()))#defining test_grades as a list
sum_extra = -999 #defining sum_extra that holds negative integer value
sum_extra = 0#defining sum_extra that holds value
for y in range(len(test_grades)):#defining a for loop to check range of list
if(test_grades[y] > 100):# defining if block that check list value is greater then 100
sum_extra = sum_extra + (test_grades[y] - 100)#use sum_extra variable to hold extra value and add this value
print('Sum extra:', sum_extra)#print value
Output:
101 83 107 90
Sum extra: 8
Explanation:
In the above code a, "list_val" variable is declared, that uses an input method to input the values and declared a "test_grades" variable that uses a list method to add all values in the list.
In the next step, the "sum_extra" variable is declared, which holds some values and defines a for loop to check the range of the "test_grades", and define a if block, that checks list value is greater than 100. If the condition is true, it will remove the extra value, and add it into the sum_extera variable and add its value, and at the last use, print variable to print its value.
<span>14. A mesh represents a(n) _____ object if its faces enclose a positive and finite amount of space. (1 point)
odd
connected
simple
convex
15. Which of the following is the 3-D view port? (1 point)
the standard layout used for new files
the polygon viewing on the default screen
straight line segments connecting two vertices
a single static image in 3-D
The answer for number 1, should be:
SOLID
</span><span>A mesh represents a solid object if its faces enclose a positive and finite amount of space
</span>
The answer for the second question is:
a single static image in 3-D
