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dimaraw [331]
3 years ago
5

What are storage devices ​

Computers and Technology
2 answers:
devlian [24]3 years ago
6 0

Answer:

<em>=</em><em>></em><em>. </em><em>storage</em><em> </em><em>devices</em><em> </em><em>are</em><em> </em><em>those</em><em> </em><em>devices</em><em> </em><em>that </em><em>is </em><em> </em><em>used </em><em>to </em><em>store</em><em> </em><em>some </em><em>data </em><em>in </em><em>it </em>

<em>It </em><em>is </em><em>very </em><em>important</em><em> </em><em>device</em><em> </em><em>that </em><em>gives </em><em>a </em><em>lot </em><em>of </em><em>benefits</em><em> </em><em>in </em><em>our </em><em>daily</em><em> lives</em>

<em>we </em><em>can </em><em>also </em><em>carry</em><em> </em><em>our </em><em>data </em><em>from </em><em>one </em><em>place</em><em> to</em><em> </em><em>another</em>

Alexxx [7]3 years ago
3 0
Well they are pretty much what store files and such on your computer or other device some different types are ssd and hdd
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A sinewave has a period (duration of one cycle) of 645 μs. What is the corresponding frequency of this sinewave, in kHz, express
irga5000 [103]

The corresponding frequency of this sinewave, in kHz, expressed to 3 significant figures is: <em>155 kHz.</em>

<u>Given the following data:</u>

  • Period = 645 μs

Note: μs represents microseconds.

<u>Conversion:</u>

1 μs = 1 × 10^{-6} seconds

645 μs = 645 × 10^{-6} seconds

To find corresponding frequency of this sinewave, in kHz;

Mathematically, the frequency of a waveform is calculated by using the formula;

Frequency = \frac{1}{Period}

Substituting the value into the formula, we have;

Frequency = \frac{1}{645\; * \;10^{-6}}

Frequency = 1550.39 Hz

Next, we would convert the value of frequency in hertz (Hz) to Kilohertz (kHz);

<u>Conversion:</u>

1 hertz = 0.001 kilohertz

1550.3876 hertz = X kilohertz

Cross-multiplying, we have;

X = 0.001 × 1550.39

X = 155039 kHz

To 3 significant figures;

<em>Frequency = 155 kHz</em>

Find more information: brainly.com/question/23460034

5 0
3 years ago
When is the following expression true? (2 points)
ipn [44]

Answer:

1) If and only if a and b have different values

Explanation:

Given

Expression: !(!a || b) || (!a && b)

Required

When is it true?

The expression is true when the values a and b are different and the proof is as follows.

(1) Assume that: a = true and b = false

!(!a || b) || (!a && b)  

= !(!true || false) || (!true && false)

!true = false, so the expression becomes:

= !(false|| false) || (false && false)

In boolean, false|| false = false and false && false = false. So, we have:

= !(false) || (false)

!(false) = true, so, the expression becomes:

= true || (false)

Lastly, true || false = true

(2) Assume that: a = false and b = true

!(!a || b) || (!a && b)  

= !(!false|| true) || (!false && true)

!false = true, so the expression becomes:

= !(true|| true) || (true && true)

In boolean, true|| true = true and true && true = true. So, we have:

= !(true) || (true)

!(true) = false, so, the expression becomes:

= false|| true

Lastly, false || true = true

<em>This expression is false if a and b have the same value</em>

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