Help…………….………thanks

Brandon swims several times per week in a lake near his home. Last summer, the average water temperature was 20 °C. This summer,

PilotLPTM [1.2K]

Answer:

0.15

Step-by-step explanation:

17/20=.85

1-.85=15

7 0

4 years ago

Mrs. Kelly bought a bag of flour that holds 1623 cups of flour. Each loaf of banana bread uses 23 cup of flour.

adoni [48]

Answer:

69 loaves

Step-by-step explanation: (Sorry if you don't understand I am not that good at explaining)

First you need to divide 1,623 by 23 because each loaf is 23 cups of flour.

So 1,623 divided by 23 equals 70.56 but you can't have a fractioned number so it needs to be a whole loaf of bread so she can make 69 loaves of bread

8 0

3 years ago

Read 2 more answers

A sequence has its first term equal to 3, and each term of the sequence is obtained by adding 5 to the previous term. If f(n) re

xxTIMURxx [149]

F(1) = 3
f(2) = 3 + 5 = 8
f(3) = 8 + 5 = 13

f(n) = 5(n - 1) + 3

f(n) = 5n - 2

4 0

3 years ago

ryan takes a 30 centimeter by 72 centimeter sheet of paper and cuts from one corner of the paper to diagonally opposite corner.

nikklg [1K]

Answer:

178

Step-by-step explanation:

Use Pythagorean Theorem to find the Hypotenuse

30^2+72^2=78^2

Use perimeter formula

a+b+c

38+72+30

3 0

3 years ago

Read 2 more answers

A study is done by a community group in two neighboring colleges to determine which one graduates students with more math classe

stealth61 [152]

Answer:

$t=\frac{(4-3.5)-0}{\sqrt{\frac{1.5^2}{11}+\frac{1^2}{9}}}}=0.890$

The p value for this case would be:

$p_v =P(t_{18}>0.890)=0.193$

The p value is higher than the significance level so then we can conclude that we can FAIL to reject the null hypothesis and then the true mean for group A is not significantly higher than the mean for B

Step-by-step explanation:

Information given

$\bar X_{1}=4$ represent the mean for sample A

$\bar X_{2}=3.5$ represent the mean for sample B

$s_{1}=1.5$ represent the sample standard deviation for A

$s_{2}=1$ represent the sample standard deviation for B

$n_{1}=11$ sample size for the group A

$n_{2}=9$ sample size for the group B

$\alpha=0.1$ Significance level provided

t would represent the statistic

Hypothesis to test

We want to verify if the student who graduates from college A has taken more math classes, on the average, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2} \leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

The statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=11+9-2=18$

Replacing we got:

$t=\frac{(4-3.5)-0}{\sqrt{\frac{1.5^2}{11}+\frac{1^2}{9}}}}=0.890$

The p value for this case would be:

$p_v =P(t_{18}>0.890)=0.193$

The p value is higher than the significance level so then we can conclude that we can FAIL to reject the null hypothesis and then the true mean for group A is not significantly higher than the mean for B

5 0

4 years ago