Answer:
The choice of the answer is fourth option that is -61 degrees.
Therefore the temperature drop is -61°Centigrade.
Explanation:
Given:
The temperature in a town started out at 55 degrees
Start temperature = 55°Centigrade. (Initial temperature)
End of the Day = -6°Centigrade. (Final temperature)
To Find:
How far did the temperature drop?
Solution:
We will have,
Substituting the above values in it we get
Therefore the temperature drop is -61°Centigrade.
Answer:
2.275x10⁶g of CN⁻¹ were dissolved in the sample
Explanation:
Molarity is defined as the ratio between moles of solute and liters of solution.
If a CN⁻¹ solution has a concentration of 25mM, there are 0.025 moles of CN⁻¹ per liter of solution.
If the sample has a colume of 3.5x10⁶L, moles of CN⁻¹ are:
3.5x10⁶L × (0.025moles / L) = <em>8.75x10⁴ moles of CN⁻¹ in the sample of water.</em>
In grams (As molar mass of CN⁻¹ is 26g/mol):
8.75x10⁴ moles CN⁻¹ × (26g / mol) = <em>2.275x10⁶g of CN⁻¹ were dissolved in the sample</em>
Answer:
Explanation:
Oxyacids are acid containing oxygen; they are also known as acid-alcohol or acid-phenol. As said earlier, the strength of these acids increases with increases in the polarity of these compounds. So, what makes the polarity is as a result of the electronegative substituents attached to it. Halogen family possesses the highest electronegativity in the periodic table, and electronegativity decreases down the group.
The ranking of the oxyacids in order of decreasing acid strength from strongest to weakest acid is:
HClO3 > . HClO2 > HClO > HBrO
Answer:
Right
Explanation:
The given parameters are;
The soluble sulfate formed by the metal, M = M₂SO₄
In the galvanic cell formed by the metal M, we have;
The concentration of M₂SO₄ in the left half cell = 50.0 mM = 0.05 M
The concentration of M₂SO₄ in the right half cell = 5.00 M
In the galvanic cell, the metal 'M' will be dissolved into the solution with lower concentration as M²⁺ which is the left half cell, making the cell negative and the solution more concentrated
In the right half cell, the metal 'M²⁺' in the solution will be plated unto the electrode making the solution less concentrated and the electrode in the right half cell will be the positive electrode
Therefore;
The electrode which will be positive is the electrode in the right half cell.
Answer:1 grams Mg(OH)2 = 0.017146870490373 mole using the molecular weight calculator and the molar mass of Mg(OH)2.
Explanation:
