MnCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MnCl2 that dissolves.
MnCl2(s) --> Mn+(aq) + 2 Cl⁻(aq)
[Cl⁻] = 0.92 mol MnCl2/1L × 2 mol Cl⁻ / 1 mol MnCl2 = 1.8 M
The answer to this question is [Cl⁻] = 1.8 M
Answer:
could be reduced by one-quarter.
Explanation:
Given :
A certain compound contains 4.0 g of calcium and 7.1 g of chlorine.
Its relative molecular mass is 111.
To Find :
Its empirical and molecular formulas.
Solution :
Moles of calcium ,
.
Moles of chlorine ,
.
The ratio calcium and chlorine is 1 : 2 .
So , the empirical formula is
.
Now , molecular mass of
is :

So , 
Therefore , the molecular formula is also
.
Hence , this is the required solution .
Answer:
Here's what I get
Explanation:
I followed the instructions and got the diagram below.