Answer:
Part 1) The points 1,2 and 4 are part of the solution
Part 2) The point 2 is not part of the solution
Part 3) Option 2. Dashed line, shade below
Part 4) The system of inequalities is


Step-by-step explanation:
Part 1) we have

Using a graphing tool
The graph in the attached figure
we know that
If a ordered pair is a solution of the inequality, then the ordered pair must be belong to the shaded area of the solution
Plot the points
The points , 1,2 and 4 belong to the shaded area
therefore
The points 1,2 and 4 are part of the solution
Part 2) we have

Using a graphing tool
The graph in the attached figure
we know that
If a ordered pair is a solution of the inequality, then the ordered pair must be belong to the shaded area of the solution
Plot the points
The point 2 not belong to the shaded area
therefore
The point 2 is not part of the solution
Part 3) we have
-----> first inequality
-----> second inequality
we know that
The solution of the second inequality is the shaded area below to the dashed line
The equation of the dashed line is 
Part 4)
Let
x------> the number of hours at work as a cashier
y------> the number of hours at work as a baby sit
we know that

Simplify
-----> inequality A
----> inequality B
-----> inequality C
-----> inequality D
The solution is the shaded area
see the attached figure