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2 years ago

I GIVEEE BRAINL,ILSTTT

Mathematics

2 answers:

yKpoI14uk [10]2 years ago

7 0

Answer:

it is d of course

Step-by-step explanation:

Ulleksa [173]2 years ago

4 0

Answer:

Step-by-step explanation:

add both the car and college payments together and divide by 1200 then multiply by 100 to get the pergecntage.

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Quiz: Completing the Square 7 Solving Quadratic Equations

galina1969 [7]

Answer:

Step-by-step explanation:

x²-5x=12

x²-5x+(\frac{-5}{2})²=12+(frac{-5}{2})²

$(x-\frac{5}{2} )^2=12+\frac{25}{4} =\frac{73}{4} \\x=\frac{5}{2} \pm\frac{\sqrt{73} }{2}=2.5 \pm 4.272\\x\approx 6.772,-1.772\\\\x \approx 06.77,-1.77$

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3 years ago

Diagram NOT accurately drawn

fredd [130]

Answer:

5x+60 = 360, x = 60

Step-by-step explanation:

Ok, so the key to this problem is to realize that all angles added up in a quadrilateral give you 360 degrees. This means that x+10 + 2x + 2x + 50 = 360. Then we can just simplify to 5x + 60 = 360, 5x = 300, and x = 60.

7 0

3 years ago

Read 2 more answers

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$