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2 years ago

Which of the following is a geometric sequence with a common ratio of 2?

1 answer:

6 0

The answer C.
Since the common ratio is 2
You just need to multiply each number with two to get the next number
14x2=28
28x2=56
56x2= 112

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Quadrilateral ABCD has vertices A(1, -3) , B(2, 1), C(6, 3), and D(7, -1). Prove or disprove that the Quad ABCD is a rectangle.

zavuch27 [327]

If AC=BD, than Quad ABCD is a rectangle
AC
√(3+3)²+(6-1)²
√6²+5²
√36+25
√61
BD
√(1+1)²+(2-7)²
√2²+(-5)²
√4+25
√29
Quad ABCD is not a rectangle because √61 and √29 are not equal.

7 0

2 years ago

Determine the value of x (ill give brainliest)

Zina [86]

Answer:

I believe the answer is 7

4 0

2 years ago

Read 2 more answers

NO LINKS!! Please help me with this problem

iogann1982 [59]

${\qquad\qquad\huge\underline{{\sf Answer}}}$

The given figure shows a vertical hyperbola with its centre at origin, and as we observe the figure, we can conclude that :

Length of transverse axis is :

$\qquad \sf \dashrightarrow \: 2b = 12$

$\qquad \sf \dashrightarrow \: b = 6$

length of conjugate axis is :

$\qquad \sf \dashrightarrow \: 2a = 8$

$\qquad \sf \dashrightarrow \: a = 4$

Equation of hyperbola ~

$\qquad \sf \dashrightarrow \: \cfrac{ {y}^{2} }{ {b}^{2} } - \cfrac{ {x}^{2} }{ {a}^{2} } = 1$

plug in the values ~

$\qquad \sf \dashrightarrow \: \cfrac{ {y}^{2} }{ {6}^{2} } - \cfrac{ {x}^{2} }{ {4}^{2} } = 1$

$\qquad \sf \dashrightarrow \: \cfrac{ {y}^{2} }{ {36}^{} } - \cfrac{ {x}^{2} }{ {16}^{} } = 1$

5 0

1 year ago

Read 2 more answers

Mathematical x4 - x2 ≥ 2x

kondaur [170]

X4-x2≥ 2x~~~2x≥ 2x True Because " _ " is the same thing with "=" ; and because 2x=2x then 2x≥ 2x ~~~~~~Have a nice day!!! ★★

4 0

3 years ago

Look at the picture! Express the following set in set-builder notation ?

Alex

Answer:

A. E={ $x|x\in N$ and $x$ is a multiple of 8}

Step-by-step explanation:

Let $x$ represent the set of natural numbers. Then we can write;

$x\in N$ .

The set of all natural numbers that are multiples of 8 is then written as;

$x\in N$ and $x$ is a multiple of 8.

E is the set of natural numbers that are multiples of 8 can then be written in set builder notation as;

E={ $x|x\in N$ and $x$ is a multiple of 8}

The correct choice is A

7 0

3 years ago