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olga nikolaevna [1]
2 years ago
5

14) If Tony HAS 5 pair of PANTS, 4 SHIRTS, BELTS AND

Mathematics
1 answer:
solniwko [45]2 years ago
4 0
He can make at-least 240
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Zara walked 3/4 mile in 30 minutes. How long will it take her to walk 2 miles?
Talja [164]

Answer:

80 minutes

Step-by-step explanation:

(3/4)/30=2/x

cross product

30*2=(3/4)x

60=3/4x

x=60/(3/4)

x=(60/1)(4/3)

x=240/3

x=80

5 0
3 years ago
What are 3 equivalent ratios to 3:11
Helen [10]

Answer:

three equivalent ratios will be

6:22 , 9:33, 15:55

6 0
3 years ago
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
Read 2 more answers
Find the midpoint of each line segment
devlian [24]

Answer:

(\frac{7}{2},\frac{1}{2})

Step-by-step explanation:

For this you use the midpoint formula

(\frac{x_{2} +x_{1} }{2} ,\frac{y_{2} +y_{1} }{2} )

the points would be (2,1) and (5,2)

The midpoint would be (\frac{7}{2},\frac{1}{2})

5 0
2 years ago
What is the surface area of a triangular prism?​
Llana [10]

Answer:

The general formula for the total surface area of a right prism is T. S. A. =ph+2B where p represents the perimeter of the base, h the height of the prism and B the area of the base.

Step-by-step explanation:

5 0
3 years ago
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