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3 years ago

Would HL ASA SAS AAS or SSS be used to justify that the pair of triangle is congruent

Mathematics

2 answers:

Vinil7 [7]3 years ago

4 0

I think that it does

Fudgin [204]3 years ago

4 0

Yes all those criterias can be used to prove that a pair of triangle is congruent.
but remember you cannot use just any of the criteria as you like. the criteria that you choose to use should match with the triangle’s given info

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What is the range of the function g(x) = |x - 12| - 2?

HACTEHA [7]

Answer:

{y|y≥−2}

Step-by-step explanation:

The domain is {x|x∈R}

The range is {y|y≥−2}

7 0

3 years ago

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Write the equation of the circle with center (3,2) and with (9,3) being a point on the circle

miss Akunina [59]

Answer:

$(x-3)^2 + (y-2)^2 = 37$

Step-by-step explanation:

To write the equation of a circle, use the formula $(x-h)^2+(y-k)^2 = r^2$ where the center of the circle is (h, k).

This means the equation is $(x-3)^2 + (y-2)^2 = r^2$ .

Find the radius r by finding the distance between (3,2) and (9,3) using the distance formula.

$d = \sqrt{(9-3)^2 + (3-2)^2} =\sqrt{6^2 + 1^2} =\sqrt{36+1} =\sqrt{37}$

Since the radius is √37 and therefore $r^2 = 37$ .

The equation is $(x-3)^2 + (y-2)^2 = 37$ .

6 0

3 years ago

Evaluate 12.3s + 11.5t when s = 7 and t = 8

dlinn [17]

Answer: 178.1
(12.3x7)+(11.5x8)
86.1+92=178.1

6 0

3 years ago

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You are testing the claim that the proportion of men who own cats is smaller than the proportion of women who own cats. You samp

MariettaO [177]

Answer:

Given:You sample 160 men, and 25% own cats

You sample 120 women, and 20% own cats.

To Find : Find the test statistic, rounded to two decimal places.

Solution:

You sample 160 men, and 25% own cats.

No. of men have cats = $\frac{25}{100} \times 160$

= $40$

So, $n_1=160 , y_1=40$

You sample 120 women, and 20% own cats.

No. of women have cats = $\frac{20}{100} \times 120$

= $24$

So, $n_2=120 , y_2=24$

We will use Comparing Two Proportions

$\widehat{p_1}=\frac{y_1}{n_1}$

$\widehat{p_1}=\frac{40}{160}$

$\widehat{p_1}=0.25$

$\widehat{p_2}=\frac{y_2}{n_2}$

$\widehat{p_2}=\frac{24}{120}$

$\widehat{p_2}=0.2$

Let $p_1$ and $p_2$ be the probabilities of men having cat and women having cat receptively

$H_0:p_1=p_2\\H_a:p_1$

$\widehat{p}=\frac{y_1+y_2}{n_1+n_2} =\frac{24+40}{160+120}=0.228$

Formula of test statistic : $\frac{\widehat{p_1}-\widehat{p_2}}{\sqrt{\widehat{p}(1-\widehat{p})(\frac{1}{n_1}+\frac{1}{n_2})}}$

Substitute the values

test statistic : $\frac{0.25-0.2}{\sqrt{0.228(1-0.228)(\frac{1}{160}+\frac{1}{120})}}$

test statistic : $0.986$

So, test statistic is 0.986

8 0

4 years ago

Please help fsdgdsfg

garri49 [273]

There is exactly one solution. 9x + 16 = 4x simplifies to 5x = 16. Dividing both sides by 5, we get

x = 16/5 (answer) (There is exactly ONE solution).

5 0

3 years ago