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lora16 [44]
3 years ago
9

How would I do 6divided by 81 in long division

Mathematics
1 answer:
Makovka662 [10]3 years ago
5 0
You would set up the long divison then you would see how much times 6 goes into 8 which 1 then a one goes in the tens place then 3 goes under the dividend then you subtract 8minus 3 and you get 5 then you bring down the one and see how much times 6 goes into 51 which is 8 then you get 48 then subtract 51 minus 48 and u get 3 so your answer is 18 r3
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Give a third degree polynomial that has zeros of 13, 5i, and −5i, and has a value of −680 when x=3. Write the polynomial in stan
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Answer:

\dfrac{17x^3-221x^2+425x-5525}{9}\\

Step-by-step explanation:

hello

we need to find something like, a being real

a(x-13)(x-5i)(x+5i)

with a so that

a(3-13)(3-5i)(3+5i)=-680\\\\a(-10)(3^2-(5i)^2)= -10(9+25)a=-360a=-680\\ a = \dfrac{680}{360}=\dfrac{17*40}{9*40}=\dfrac{17}{9}

so the third degree polynomial that we are looking for is

\dfrac{17}{9}(x-13)(x-5i)(x+5i)\\=\dfrac{17}{9}(x-13)(x^2+25)\\\\=\dfrac{17}{9}(x^3+25x-13x^2-13*25)\\\\\\=\dfrac{17}{9}(x^3-13x^2+25x-325)\\\\\\\\=\dfrac{17}{9}x^3-\dfrac{17*13}{9}x^2+\dfrac{17*25}{9}x-\dfrac{17*325}{9}\\=\dfrac{17}{9}x^3-\dfrac{221}{9}x^2+\dfrac{425}{9}x-\dfrac{5525}{9}\\

hope this helps

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