Answer:
Step-by-step explanation:
f(x) = 2x² + 14x - 4
= 2(x² + 7x) - 4
= 2(x² +7x + 3.5²) - 2(3.5²) - 4
= 2(x+3.5)² - 28.5
vertex (3.5, -28.5) = (7/2, -57/2)
The vertical intercept is the y-intercept, i.e., f(0) = -4.
The x-intercepts are the values of x for which y=0.
2x² + 14x - 4 = 0
x = [-14±√(14²-4(2)(-4))]/[2(2)] = [-7±√57]/2 ≅ -7.27, 0.27
4) The line segments formed are parallel because they never meet.
8) The answer is B. That is because there is a right angle and right angles are formed by perpendicular lines.
Hope this helps :)<span />
Answer:
21
Step-by-step explanation:
yeah 2+2 is 21 thanks for the very nonexistent question
The function
f(x) is even
g(x) is neither even nor odd
h(x) is odd
Steps:
for an even function it holds that f(-x) = f(x):
f(-x) = (-1)^6 x^6 - (-1)^4 x^ 4 = x^6 - x^4 = f(x) => f is even
for an odd h(x) it holds that h(-x) = -h(x):
![h(-x) = (-1)^5x^5-(-1)^3x^3 = -(x^5-x^3) = -h(x) \implies h(x)\,\, \mbox{even}](https://tex.z-dn.net/?f=h%28-x%29%20%3D%20%28-1%29%5E5x%5E5-%28-1%29%5E3x%5E3%20%3D%20-%28x%5E5-x%5E3%29%20%3D%20-h%28x%29%20%5Cimplies%20h%28x%29%5C%2C%5C%2C%20%5Cmbox%7Beven%7D)
It is easy to show that g(x) does not match any of the two possibilities above.