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3 years ago

Verify the identity. Show your work. 1 + sec^2xsin^2x = sec^2x

1 answer:

4 0

$\bf \textit{Pythagorean Identities}
\\\\
1+tan^2(\theta)=sec^2(\theta)\\\\
-------------------------------\\\\
1+sec^2(x)sin^2(x)=sec^2(x)
\\\\\\
1+\cfrac{1}{cos^2(x)}\cdot sin^2(x)\implies 1+\cfrac{sin^2(x)}{cos^2(x)}\\\\\\ 1+tan^2(x)\implies sec^2(x)$

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ILL GIVE BRAINELST

murzikaleks [220]

Answer:

A = 12 ft

Step-by-step explanation:

Perimeter ( of SQUARE) B = 64

then each side = 64/4 = 16

AREA of SQUARE C = 400

side X side = 400

then side = sqrt 400

Now use Pyhtagorean Theorem to find leg of right triangle that is

side A Side B hypotenuse Side C

A^2 + 16^2 = (sqrt 400)^2

A^2 = 400 - 256

A^2 = 144 then A = 12 Ft

6 0

1 year ago

Evaluate 50 + 0.5 ×(41 - 32)

Zarrin [17]

To solve this expression, we need to follow the order of operations (BEDMAS)

50+0.5(41-32)
=50+0.5(9)
=50+4.5
=54.5

Your answer is 54.5

7 0

2 years ago

eight less than four times a number is twelve. what is the number? the options are, 5 , 1 , -3 , -5 , please i need a answer asa

ra1l [238]

4x minus 8 = 12 answer: 5

6 0

3 years ago

Which two equations are true?(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)=6.6×10−10 (6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.

tiny-mole [99]

let me edit your question as:

Which two equations are true?

Eq1:

(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)

Eq2:

6.6×10−10(6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.7×103)

Eq3:

2.7×103(7.5×106)−(2.5×106)=5×100

Answer:

No one is true

Step-by-step explanation:

let's check each equation, if the values on both sides (left and right side) are equal then the equation is true otherwise false.

Using PEMDAS rule we are simplifying the equations as;

Eq1:

$(2*10-4)+(1.5*10-4)=3.5*10-4(3*10-5)+(2.2*10-5)\\(16)+(11)=35-4(25)+(17)\\27=35-100+17\\27=-48\\$

Eq2:

$6.6*10-10(6.3*10-1)-(2.1*10-1)=3*10-1(5.4*103)-(2.7*103)\\66-10(62)-(20)=30-1(556.2)-278.1\\66-620-20=30-556.2-278.1\\-574=-804.1$

Eq3:

$2.7*103(7.5*106)-(2.5*106)=5*100\\221089.5-265=500\\220824.5=500\\$

we observed that none of the equation has two same values on both sides thus none of the three equations is true.

Also, no value of Eq1, Eq2 or Eq3 are same thus none of the equation is true

8 0

3 years ago

Y=143.3(5)^2+1823.3(5)+6820

MA_775_DIABLO [31]

As the question is written, the correct answer is:

19519.

Explanation:

Our question states

y = 143.3(5)² + 1823.3(5) + 6820

To evaluate this, we use the order of operations (PEMDAS). There is nothing to be evaluated in parentheses, so P is taken care of.

The E part, exponents, is 5². This is 25, which gives us:

y = 143.3(25) + 1823.3(5) + 6820

Next we have M and D, multiplication and division (in the order they appear). Our multiplication is:

143.3(25) = 3582.5; and

1823.3(5) = 9116.5.

This gives us:

y = 3582.5 + 9116.5 + 6820

Lastly, we add these:

y = 12699 + 6820

y = 19519

6 0

3 years ago

Read 2 more answers