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3 years ago

• 1.Find the scale factor of a blueprint if the scale is 3 inches = 6 feet.

Mathematics

2 answers:

Rainbow [258]3 years ago

8 0

Answer:

Step-by-step explanation:

inysia [295]3 years ago

7 0

Answer: B. 24 (as a fraction: 1/24)

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Solve this question fast....in the attachment

avanturin [10]

Answer:

z = 4

y = -1

x = 2

Step-by-step explanation:

x - y = 3

Therefore => x = 3 + y

y + 2z =7

Therefore => y= 7 - 2z

We have the equation :

2x + 3y + 4z = 17

2(3 + y) + 3(7 - 2z) + 4z = 17

6 + 2y + 21 - 6z +4z = 17

2(7 -2z) - 2z + 27 = 17

14 - 4z - 2z + 27 = 17

-6z + 41 = 17

-6z = -24

z = 4

4 0

3 years ago

spencer is on a mountain 11,224 feet above sea level. Heidi is on a submarine 3703 feet below sea level in a direct line below S

Alex

Since heidi is on a submarine 3703 below, we could say that she's -3703 and spencer is 11,224. 11224-(-3703)=14927

6 0

3 years ago

If a 11 inch wheel cost $21.35 what is the cost per square inch

Natali [406]

Answer:

$1.94 per square inch

8 0

3 years ago

Bobby catches 8 passes in 3 football games. At this rate how many passes dose he catch in 15 games?expine

stepan [7]

Answer: 40

Step-by-step explanation:

I can see the answer is 40, but let's try to figure out how to do it.

I like to use the rule of 3. Let's put the number of passes on the left side and the number of games on the right side.

$\frac{8}{x}=\frac{3}{15}$

''x'' represents the number of passes in 15 games.

Solve for x;

$x=\frac{15*8}{3}\\ x=\frac{120}{3}\\ x=40$

8 0

4 years ago

PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The

Nookie1986 [14]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}$

<h3>Step-by-step explanation:</h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

Radius of smaller circle be r .
Radius of smaller circle be r .
Area of shaded region be $\bf Area_{shaded}$

$\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2 \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2) \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2] \\\\\bf\implies Area_{shaded} = \pi [ 100cm^2-16cm^2] \\\\\bf\implies Area_{shaded} = \pi \times 84cm^2 \\\\\bf\implies Area_{shaded} = \dfrac{22}{7}\times 84cm^2 \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}$

<h3>Hence the area of the shaded region is 264 cm².</h3>

5 0

3 years ago