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1 year ago

Which of the following graphs represents the equation y = 2x + 2?

Mathematics

2 answers:

lbvjy [14]1 year ago

8 0

the answer is the litter B

lisov135 [29]1 year ago

7 0

Answer:

B.) Graph B

Step-by-step explanation:

You can determine which is the correct graph by verifying the points on the graphs with the equation. Remember, the leftmost number in the parentheses is the "x-value" and the rightmost number is the "y-value".

Graph B has the points (0,2) and (2,6) on the line.

y = 2(0) + 2

y = 2

y = 2(2) + 2

y = 4 + 2

y = 6

As you can see, when the "x-values" are plugged into the equation, the value generated matches the "y-value" of the point. Not all the points on the other graphs are accurate according to the equation. You can prove this to yourself by following the same method as above.

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Can someone help me plz

joja [24]

is it from a textbook

7 0

2 years ago

Alex scored 70% in a spelling test with 20 quetions

amm1812

Answer:

This means that Alex answered 14 questions correctly

Step-by-step explanation:

<u>Step 1: Find an equation</u>

20 * 0.7 = x

<u>Step 2: Multiply</u>

20 * 0.7 = x

14 = x

Answer: This means that Alex answered 14 questions correctly

5 0

2 years ago

Read 2 more answers

(x^2 - x^(1/2))/(1-x^(1/2))

Levart [38]

$\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 } } \right) }{ \left( 1-{ x }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot 1$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot \frac { \left( 1+\sqrt { x } \right) }{ \left( 1+\sqrt { x } \right) }$

$\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }$

$\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\} }{ \left( 1-x \right) }$

$\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }\left( 1+{ x }^{ \frac { 2 }{ 2 } } \right) -x$

$\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }-{ x }^{ \frac { 3 }{ 2 } }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x$

3 0

2 years ago

Read 2 more answers

2. If tan theta = 2 , find cot theta

RideAnS [48]

Answer:

1/2

Step-by-step explanation:

cot∅ = 1/tan∅

cot∅ = 1/2

3 0

2 years ago