Question

What is an equation of the line that passes through the points (4, -5) and (2, 0)?

Answer 1

Answer:

y = - $\frac{5}{2}$ x + 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (4, - 5) and (x₂, y₂ ) = (2, 0)

m = $\frac{0+5}{2-4}$ = $\frac{5}{-2}$ = - $\frac{5}{2}$ , then

y = - $\frac{5}{2}$ x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (2, 0 )

0 = - 5 + c ⇒ c = 0 + 5 = 5

y = - $\frac{5}{2}$ x + 5 ← equation of line