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alexdok [17]
2 years ago
11

an apple and a banana cost $2.10 the apple is $2.00 more than the banana how much does the banana cost

Mathematics
1 answer:
Korolek [52]2 years ago
8 0
$2.10 - $2 = $0.10

The banana cost 10 cents.
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jasmine bought wax that will cover 400 square feet per gallon. jasmine needs to wax 4704 square foot surface with 2 coats of wax
WINSTONCH [101]

Answer:

24

Step-by-step explanation:

400 × 12 = 4,800

4,800 needed for ONE coat.

Since you need TWO coats, double 12, then you should get 24.

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4 hours worked for $12; 7 hours worked for $28l
777dan777 [17]

Answer:

$293.00

Step-by-step explanation:

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3 years ago
Please Help. If ∠P is given as well as the values of p, q, and r, then explain whether the Law of Sines or the Law of Cosines sh
sertanlavr [38]

Answer:

Both Law of Sines and Cosines can be used to determine the angle Q.

Step-by-step explanation:.

Since from Law of Sines with one angle and three sides we can find other angles using the ratio obtained with the given angle and side length opposite side if angle P is not given we couldn't use this.

Law of Cosines can be used to find any angle of triangle with all three side lengths given and angle P is also not required to find angle Q.

3 0
3 years ago
Read 2 more answers
Please help me with this one
Alex73 [517]

Answer:

2×5×7+2×5×2+2×7×2

70+20+28

108cm^2

3 0
3 years ago
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Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y
kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

substitute in the formula

d=\sqrt{(5-2)^{2}+(2-0)^{2}}

d=\sqrt{(3)^{2}+(2)^{2}}

dAB=\sqrt{13}\ units

step 2

Find the distance BC

substitute in the formula

d=\sqrt{(7-5)^{2}+(-1-2)^{2}}

d=\sqrt{(2)^{2}+(-3)^{2}}

dBC=\sqrt{13}\ units

step 3

Find the distance AC

substitute in the formula

d=\sqrt{(7-2)^{2}+(-1-0)^{2}}

d=\sqrt{(5)^{2}+(-1)^{2}}

dAC=\sqrt{26}\ units

step 4

Compare the length sides

dAB=\sqrt{13}\ units

dBC=\sqrt{13}\ units

dAC=\sqrt{26}\ units

dAB=dBC

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

(AC)^{2} =(AB)^{2}+(BC)^{2}

substitute

(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}

26=13+13

26=26 -----> is true

therefore

Is an isosceles right triangle

8 0
3 years ago
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