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2 years ago

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the

Mathematics

2 answers:

worty [1.4K]2 years ago

7 0

Answer:

The maximum height is 1087.06 ft.

Step-by-step explanation:

We need to take the derivative of the equation and set it to 0.

$y' = - 32x + 254 = 0\\32x = 254\\x = 7.9375$

We now can plug x = 7.9375 into the original equation.

$y=-16x^{2} +254x+79\\y=-16(7.9375)^{2}+254(7.9375)+79\\y=1087.06 ft$

zimovet [89]2 years ago

6 0

Answer:

1087.1

Step-by-step explanation:

same as the other comment it's just that if your on delta math they make you round.

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Find the LCD of the following list of fractions. 2/21, 10/14, 17/22 LCD=

ollegr [7]

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2 years ago

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Alekssandra [29.7K]

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2 years ago

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$