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3 years ago

$25.00 With a 10% discount. $27.00 With a 20% discount. $26.00 Whit a 15% discount. Witch one is cheaper?

Mathematics

1 answer:

olasank [31]3 years ago

7 0

Answer:

i think its $27.00 with a 20% discount

Step-by-step explanation:

$25 with a 10% discount is $22.50, $26 with a 15% discount is $22.10, and $27 with a 20% discount is $21.60. Therefore the cheapest option is $27.00 with a 20% discount.

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Drag the tiles to list the sides of △MNO from shortest to longest.

sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

MO/Shortest MO/Medium and MO/Longest

a) Friday

b) 70 minutes

c) 40%

d) Yes, the sum of the mean number of minutes spent on aerobic training and the mean number of minutes spent on strength training is equal to the mean total number of minutes spent training.

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= $\frac{}{MO}$

The next shortest side is the side opposite ∠M(61°) = $\frac{}{NO}$

The longest side is the side opposite ∠O(65°) = $\frac{}{MN}$

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on Friday

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = 70 minutes

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

$The$ $percentage$ $spent$ $on$ $strength$ $training$ = $\frac{120}{300}$ × $100 =$ $\frac{40}$ %

d) The mean number of minutes spent on strength training is found as follows;

$Mean_{strength} =\frac{120}{5} =24$

The mean number of minutes spent on aerobic training is found as follows;

$Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36$

$Mean_{strength} +Mean_{aerobic} =24+36=60$

The mean total number of minutes spent training, $Mean_{total}$ = $\frac{300}{5}$ = 60

Therefore;

$Mean_{strength}+Mean_{aerobic} = Mean_{total} \\$

Learn more here:

brainly.com/question/2962546

4 0

2 years ago

Resuelve las ecuaciones 3(2x-1)+5(x-3)=4x+7 5-x-(2x+3)= 3+8x

Ivan

Let's solve your equation step-by-step.3(2x−1)+5(x−3)=4x+7Step 1: Simplify both sides of the equation.3(2x−1)+5(x−3)=4x+7Simplify:11x−18=4x+7Step 2: Subtract 4x from both sides.11x−18−4x=4x+7−4x7x−18=7Step 3: Add 18 to both sides.7x−18+18=7+187x=25Step 4: Divide both sides by 7.7x7=257x=257Answer:x=257


Let's solve your equation step-by-step.5−x−(2x+3)=3+8xStep 1: Simplify both sides of the equation.5−x−(2x+3)=3+8xSimplify:−3x+2=8x+3Step 2: Subtract 8x from both sides.−3x+2−8x=8x+3−8x−11x+2=3Step 3: Subtract 2 from both sides.−11x+2−2=3−2−11x=1Step 4: Divide both sides by -11.−11x−11=1−11x=−111Answer:x=−111
Espero que esto ayude

4 0

2 years ago

Read 2 more answers

Help will mark brainiest!

Darya [45]

Answer:

Sry Im guessing. You divide the actual length of pole by the shadow then multiply it to shadow of the tower...

Step-by-step explanation:

Hope it helps

6 0

2 years ago

Write and equation for the shift of the parent graph y=1/x

SashulF [63]

You can think of this equation as $\bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}$

and thus apply the transformations to it as such

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

1) D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7

7 0

2 years ago

How do you explain a math equation?

svet-max [94.6K]

By doing doing the math question and explaining it at the same time

4 0

2 years ago