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tia_tia [17]
3 years ago
8

A group goes on a nature walk and identifies all the edible plants encountered. What type of data is this?

Mathematics
2 answers:
Len [333]3 years ago
8 0
It is considered categorical data. Categorical data is the edible plants that are encountered.
Nezavi [6.7K]3 years ago
8 0

Answer:Categorical data

Step-by-step explanation:

A group of all the edible plants represent the categorical data or Qualitative data  as categorical data have no logical order .

Analysis of categorical data  includes data  tables.Examples of categorical data are race, educational level ,age,sex .

Categorical data are of two type

  • Nominal
  • ordinal
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2 years ago
I need to do this problem by completing the square . help please
sukhopar [10]

Answer:

the roots are n = 1 + √15 and n = 1 - √15

Step-by-step explanation:

In this case I would immediately rewrite n² - 2n - 5 = 10 as

n² - 2n                  = 10 + 5 = 15.

To complete the square:  Identify the coefficient of n (it is -2). Halve that, obtaining -1, square this result, and then add the outcome (1) to and subtract the outcome (1) to n² - 2n:

n² - 2n  <em>+ 1 - 1   </em>             = 15

Next, rewrite n² - 2n  + 1 as the square of a binomial:

(n - 1)² = 15

Finally, take the square root of both sides:

n - 1 = ±√15

so that the roots are n = 1 + √15 and n = 1 - √15

8 0
3 years ago
Two mechanics worked on a car. The first mechanic charged $115 per hour, and the second mechanic charged $50 per hour. The mecha
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Read 2 more answers
Please answer all please​
Firdavs [7]

Answer:

Step-by-step explanation:

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We plug these values into the given vertex form equation of a parabola:

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Next, we subst. the coordinates of the y-intercept (0, 1) into the above, obtaining:

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y = (x + 1)^2

Second parabola:  We follow essentially the same approach.  Identify the vertex and the two horizontal intercepts.  They are:

vertex:  (1, 4)

x-intercepts:  (-1, 0) and (3, 0)

Subbing these values into y - k = a(x - h)^2, we obtain:

                                            0 - 4 = a(3 - 1)^2, or

                                                -4 = a(2)².  This yields a = -1.

Then the desired equation of the parabola is

y - 4 = -(x - 1)^2

7 0
3 years ago
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