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3 years ago

6

6 divided by 1 over 5

2 answers:

alina1380 [7]3 years ago

5 0

Answer:

6/5

Step-by-step explanation:

kari74 [83]3 years ago

4 0

Answer:

30

Step-by-step explanation:

Use KCF method

K - keep the first number

C- Change the operation - division to multiplication

F - Flip the second number

6 ÷ $\frac{1}{5}$ = 6 * $\frac{5}{1}$

= 6 * 5

= 30

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While eating dinner, Marian ate 25% of the apple slices she had in her bag. There were 20 apple slices in her bag. How many appl

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Answer:

She ate 5 apple slices

Step-by-step explanation:

25% of 20 is 5.

That means if she ate 5 slices, she ate 25% of the apple slices.

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3 years ago

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Find HCF of 96 and 404 by prime factorization method and find their LCM

viktelen [127]

Answer:

HCF of 96 and 404 by prime factorisation method:-

Since, 96 = 2 × 2 × 2 × 2 × 2 × 3

and, 404 = 2 × 2 × 101

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= 2 × 2 = 4

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Step-by-step explanation:

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4 0

4 years ago

Please help with these partial fractions!!!

VARVARA [1.3K]

a. Factorize the denominator:

$\dfrac{x+14}{x^2-2x-8}=\dfrac{x+14}{(x-4)(x+2)}$

Then we're looking for $a,b$ such that

$\dfrac{x+14}{x^2-2x-8}=\dfrac a{x-4}+\dfrac b{x+2}$

$\implies x+14=a(x+2)+b(x-4)$

If $x=4$ , then $18=6a\implies a=3$ ; if $x=-2$ , then $12=-6b\implies b=-2$ . So we have

$\dfrac{x+14}{x^2-2x-8}=\dfrac3{x-4}-\dfrac2{x+2}$

as required.

b. Same setup as in (a):

$\dfrac{-3x^2+5x+6}{x^3+x^2}=\dfrac{-3x^2+5x+6}{x^2(x+1)}$

We want to find $a,b,c$ such that

$\dfrac{-3x^2+5x+6}{x^2(x+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac c{x+1}$

Quick aside: for the second term, since the denominator has degree 2, we should be looking for another constant $b'$ such that the numerator of the second term is $b'x+b$ . We always want the polynomial in the numerator to have degree 1 less than the degree of the denominator. But we would end up determining $b'=0$ anyway.

$\implies-3x^2+5x+6=ax(x+1)+b(x+1)+cx^2$

If $x=0$ , then $b=6$ ; if $x=-1$ , then $c=-2$ . Expanding everything on the right then gives

$-3x^2+5x+6=ax^2+ax+bx+b+cx^2=(a-2)x^2+(a+6)x+6$

which tells us $a-2=-3$ and $a+6=5$ ; in both cases, we get $a=-1$ . Then

$\dfrac{-3x^2+5x+6}{x^2(x+1)}=-\dfrac1x+\dfrac6{x^2}-\dfrac2{x+1}$

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4 years ago

Please help ASAP.....

Andre45 [30]

Answer:

a

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Answer:

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