Answer:
I guess so.........................................................
Answer:
(3, 50) and (14,303)
Step-by-step explanation:
Given the system of equations;
y=23x–19 ....1
x²–y= – 6x–23 ...2
Substitute 1 into 2;
x²–(23x-19)= – 6x–23
x²–23x+19= – 6x–23 .
x²-23x + 6x + 19 + 23 = 0
x² - 17x + 42 = 0
Factorize;
x² - 14x - 3x + 42 = 0
x(x-14)-3(x-14) = 0
(x-3)(x-14) = 0
x = 3 and 14
If x = 3
y = 23(3) - 19
y = 69-19
y = 50
If x = 14
y = 23(14) - 19
y = 322-19
y = 303
Hence the coordinate solutions are (3, 50) and (14,303)
Answer:
The year is
Step-by-step explanation:
From the question we are told that
The percentage of the number of babies born out of wedlock in 1990 is k = 28%
The percentage by which the number increase per year is i = 0.6%
The percentage of of the number of babies born out of wedlock considered is a = 31%
Generally the difference in between the percentage in 1990 and the percentage considered is

=> 
=> 
Generally the number of year require for the percentage to be equal to 31% is mathematically represented as

=> 
Generally the year which the considered percentage will be attained is

=>
=>
I think it would be 12(2-3)
Hope this helps!
1. BC is 1+3=4 (units)
2. AD is 3+5= 8 (units)
3. Draw the altitude CH from point C, as shown in the figure.
4. Then triangle CHD is a right triangle, with hypothenuse CD, and sides HD and CH.
5.



6. AB=CD=4.47 because the trapezoid is isosceles.
7. P= BC+AD+AB+CD=4+8+4.47+4.47=20.9 (units)