$g(x)=4x-\dfrac{1}{4x}=4x-(4x)^{-1}\\\\\\\\g'(x)=\left[4x-(4x)^{-1}\right]'=(4x)'-\left[(4x)^{-1}\right]'=4-[-1(4x)^{-2}]\cdot4\\\\=4+\dfrac{1}{(4x)^2}\cdot4=4+\dfrac{4}{4^2x^2}=\boxed{4+\dfrac{1}{4x^2}}\\\\Used:\\\\(f(x)-g(x))'=f'(x)-g'(x)\\\\.[f(g(x))]'=f'(g(x))\cdot g'(x)\\\\(x^n)'=nx^{n-1}$

8 0

3 years ago

How many tiles are added to each figure in the tile pattern shown above

DENIUS [597]

Answer:

4 tiles are added to each figure in the tile pattern.

6 0

3 years ago

suppose you have 192 marbles in groups of 15 marbles each. Find the number of groups of marbles that you have. Write the quotien

stepan [7]

So if you have 192 marbles and you want to group them in groups of 15 marbles each
you would see how many times 15's there are in 192 or how many 192's would go into 15

so 192/15 or
12 and 12/15

8 0

3 years ago

Read 2 more answers

The Sugar Sweet Company is going to transport its sugar to market. It will cost

Troyanec [42]

Im not going to graph it for you but the equation is

C=7250+250s

4 0

3 years ago