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Ber [7]
3 years ago
13

What is the third angle of a right triangle if one of the angles measures 51 degrees

Mathematics
2 answers:
kupik [55]3 years ago
4 0
All angles of a triangle add up to 180 degrees. If it's a right triangle, the right angle is 90 degrees. If another angle is 51 degrees then the last angle has to be 180 - 90 = 90 - 51 = 39 degrees.
BabaBlast [244]3 years ago
3 0
Since it's a right triangle one angle will be 90°
■■■■■■■■■■■■■■■■■■■■
90°+51°=141°
A triangle is 180°
180°-141°=39°

THE THIRD ANGLE WILL BE 39°
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Find the fifth roots of 243(cos 260° + i sin 260°)
Charra [1.4K]
<span>use De Moivre's Theorem:

⁵√[243(cos 260° + i sin 260°)] = [243(cos 260° + i sin 260°)]^(1/5)

= 243^(1/5) (cos (260 / 5)° + i sin (260 / 5)°)

= 3 (cos 52° + i sin 52°)

z1 = 3 (cos 52° + i sin 52°) ←← so that's the first root


there are 5 roots so the angle between each root is 360/5 = 72°

then the other four roots are:

z2 = 3 (cos (52 + 72)° + i sin (52+ 72)°) = 3 (cos 124° + i sin 124°)

z3 = 3 (cos (124 + 72)° + i sin (124 + 72)°) = 3 (cos 196° + i sin 196°)

z4 = 3 (cos (196 + 72)² + i sin (196 + 72)°) = 3 (cos 268° + i sin 268°)

z5 = 3 (cos (268 + 72)° + i sin (268 + 72)°) = 3 (cos 340° + i sin 340°) </span>
3 0
3 years ago
Solving liner equations 2×- 19=30​
ivolga24 [154]

Answer:

x=24.5

Step-by-step explanation:

1. Add 19 to both sides.

2x=49

2. Divide both sides by 2.

x=24.5

3 0
3 years ago
Is 9 a factor of 54x + 63​
Zolol [24]

Answer:

yes

Step-by-step explanation:

It is because 9 divides into 54 and 63

7 0
2 years ago
Read 2 more answers
How much was deposited in the account if the amount in the
Mrac [35]

Answer:

$98.33 was deposited in the account

Step-by-step explanation:

simple interest formula = (PRT)/100 ...where p is money, r is rate, t is time

using formula  $17.70 = (P *  3% * 6)/100

                         P = 1770/18

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8 0
2 years ago
You are working as an apprentice for the bksb Newcastle Arena.
Advocard [28]
To find the area of the arena, you will need to find the areas of the rectangular spaces and the 2 semicircles. Because the formulas are given, I will just substitute in the values and show the work for finding the areas.

To find the perimeter, you will look at the distances of lines that take you around the space. Because two of these spaces are half circles, you will need to find the circumference of the full circle.

Also, the answers need to be given in meters, so all units given in centimeters will be divided by 100 to convert them to meters.

Perimeter:

C= 3.14 x 20 m
C = 62.8 meters

62.8 + 8 + 25 + 8 + 5 + 8 + 10 + 8 + 40= 174.8 meters for the Perimeter

Area:
A = 25 x 8
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A = 10 x 8
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A = 20 x 40
A = 800 square meters

A = 3.14 x 10^2
A = 314 square meters

Total Area: 314 + 800 + 80 + 200= 1394 square meters
8 0
3 years ago
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