Answer:
(6,35)
Step-by-step explanation:
Set both equations equal to each other and solve for x
8x+11=5x+29, Subtract 5x from both sides
3x+11=29, Subtract 11 from both sides
3x=18 Divide by 3
x=6
Substitute x=6 back into either equation to solve for y
y=8(6)+11
y=48+11
y=59
<u>Given:</u>
The two equations are
and 
We need to solve the equations using elimination method.
<u>Elimination method:</u>
Let us multiply the equation
by 5, we get;
---------(1)
Now, multiplying the equation
by -2, we get;
--------(2)
Adding equations (1) and (2), we have;


Thus, the value of y is 3.
Substituting
in the equation
, we have;




Thus, the value of x is 4.
Hence, the solution of the system of equations is (4,3)
Therefore, Option A is the correct answer.
change both the fractions to improper fractions. the area will be 147/4 , and the width will be 9/2 . with both of these you may now divide, (147/4) / (9/2)
remember to use the KCF when dividing fractions.
147 * 2 = 294
4 * 9 = 36
your new fraction will be 294/36 .... which it is also 8 1/6