Por determinante:
5...1...1
1...0...1 = 0 --> se o determinante for igual a 0, os pontos estarão alinhados.
3...3...1
calculando: (5 x 0 x 1 + 1 x 1 x 3 + 1 x 3 x 1) - (1 x 0 x 3 + 1 x 1 x 1 + 3 x 1 x 5) =
0 + 3 + 3 - 0 - 1 - 15 =
6 - 1 - 15 =
5 - 15 = - 10 --> como não deu zero, os pontos não estão alinhados.
Answer:
C. m<CAB = m<C'A'B'
Step-by-step explanation:
Triangle ABC looks like it was only reflected over the line y = 0. If the triangle was only reflected then the triangles should be congruent to each other.
3y=-6
y=-2
4x+2(-2)=6
4x-4=6
4x=10
x=5/2
(5/2,-2)
-x=-2
x=2
5(2)+2y=12
10+2y=12
2y=2
y=1
(2,1)
35x+28y=84
-35x+30y=-200
58y=-116
y=-2
5x+4(-2)=12
5x-8=12
5x=20
x=4
(4,-2)
20m+8n=-32
-20m-15n=-10
-7n=-42
n=6
5m+2(6)=-8
5m+12=-8
5m=-20
m=-4
(-4,6)
