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2 years ago

Can you find the area for this?

Mathematics

2 answers:

Tanzania [10]2 years ago

8 0

Answer:

b. is the right answer of your question

yaroslaw [1]2 years ago

7 0

Answer:

106.5=0.01065

26.6=0.00266

60.35=0.00266

53.25=0.005325

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What is the value of log2 81?

mestny [16]

6.33985000288

i used a calculator

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7 0

2 years ago

Please help!!!!

meriva

answer 16.99%

We are given this function:

8700 is the initial amount.

1.04 shows the change of original amount. This is decimal form of percentage. We need to transform it into regular percentage.

1.04 * 100% = 104%

Now we observe this number. If it is greater than 100% we have growth, if it is lower than 100% it is decay, and if it is equal to 100% than there is no change.

In our case this number is greater than 100% so we have growth. To determine the percentage rate we must substract 100% as it represents the original amount.

104% - 100% = 4%

This would be our solution if we don't have an exponent.

We have exponent so first step is to calculate the number and then we repeat the steps from above.

1,16985856 * 100% ≈ 116,99%

116.99% - 100% = 16.99%

So, final solution is growth of 16.99%

bran-list please

7 0

2 years ago

The data given below contain the state cigarette taxâ€‹ (in $) for all 20 regions of a country.

g100num [7]

Answer:

(a) $\bar x= 1.583$ -- Population Mean

(b) $s = 1.032$ --- Population standard deviation

Step-by-step explanation:

Given:

Cigarette tax for 20 regions

Solving (a): The population mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

$\sum x = 1.36 + 1.70 + 2.50 + 0.45 + 1.18 + 0.64 + 3.46 + 0.57 + 2.00 + 0.80 + 1.60 +0.98 + 0.36 + 2.24 + 4.35 + 0.62 + 2.70 + 1.78 + 1.53 + 0.84$

$\sum x = 31.66$

$n = 20$

So, we have:

$\bar x= \frac{31.66}{20}$

$\bar x= 1.583$

Solving (b): The population standard deviation

This is calculated as:

$s = \sqrt{\frac{\sum( x - \bar x)^2}{n}$

$\sum (x -\bar x)^2 = (1.36 - 1.583)^2 + (1.70 - 1.583)^2+ (2.50 - 1.583)^2+ (0.45 - 1.583)^2+ (1.18 - 1.583)^2+ (0.64 - 1.583)^2+ (3.46 - 1.583)^2+ (0.57 - 1.583)^2+ (2.00 - 1.583)^2+ (0.80 - 1.583)^2+ (1.60 - 1.583)^2+(0.98 - 1.583)^2+ (0.36 - 1.583)^2+ (2.24 - 1.583)^2+ (4.35 - 1.583)^2+ (0.62 - 1.583)^2+ (2.70 - 1.583)^2+ (1.78 - 1.583)^2+ (1.53 - 1.583)^2+ (0.84- 1.583)^2$