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3 years ago

Snow is falling in syracuse, NY after 2 hours, 4 inches of snow has fallen.

Mathematics

2 answers:

kobusy [5.1K]3 years ago

7 0

Step-by-step explanation:

it snows 4/2 = 2 inches perhour

1. 2x 6.5 = 13 inches

2. y = 2z

3. 2x 24 = 48 inches

il63 [147K]3 years ago

4 0

Answer:

1) 13 inches

2) 2z=x

3) 48 inches

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△ABC ≅ △DEF, EF = x 2 - 7, and BC = 4x - 2.

Artist 52 [7]

Answer:

Therefore the value of x is 5.

Step-by-step explanation:

Given:

△ABC ≅ △DEF,

EF = x 2 - 7, and

BC = 4x - 2.

To Find:

the values of x. = ?

Solution:

△ABC ≅ △DEF ........Given

If two Triangles are congruent then the Corresponding Parts of Congruent Triangles are Congruent.

∴ BC ≅ EF ...................CPCTC

Substituting the values we get

$4x-2=x^{2}-7\\x^{2}-4x-5=0$

Now By Factorizing we get

$x^{2}-5x+x-5=0\\x(x-5)+1(x-5)=0\\(x+1)(x-5)=0\\x+1=0\ or\ x-5=0\\x=-1\ or\ x=5\\x\ cannot\ be\ negative\\\therefore x=5$

Therefore the value of x is 5.

8 0

3 years ago

Savana has read 4 pages in her new book. Carlos has read 4 times as many pages as savana. How many pages has Carlos read? I

kiruha [24]

4 x 4 = 16

Savanas pages read times 4 gives you Carlos pages.

4 0

3 years ago

A rectangular park has 2 paths of width 2m running across it. What is the total area covered by the 2 paths ?

astra-53 [7]

Answer:

10m.

Step-by-step explanation:

Add up all the areas of the running path and then you can reach to the answer. I got 10m and most probably it should be that only.

3 0

3 years ago

Use mathematical induction to show that 4^n ≡ 3n+1 (mod 9) for all n equal to or greater than 0

cestrela7 [59]

When $n=0$ , you have

$4^0=1\equiv3(0)+1=1\mod9$

Now assume this is true for $n=k$ , i.e.

$4^k\equiv3k+1\mod9$

and under this hypothesis show that it's also true for $n=k+1$ . You have

$4^k\equiv3k+1\mod9$
$4\equiv4\mod9$
$\implies 4\times4^k\equiv4(3k+1)\mod9$
$\implies 4^{k+1}\equiv12k+4\mod9$

In other words, there exists $M$ such that

$4^{k+1}=9M+12k+4$

Rewriting, you have

$4^{k+1}=9M+9k+3k+4$
$4^{k+1}=9(M+k)+3k+3+1$
$4^{k+1}=9(M+k)+3(k+1)+1$

and this is equivalent to $3(k+1)+1$ modulo 9, as desired.

3 0

3 years ago

Find the value of the variable 10 45

Ratling [72]

Answer:

35.

Step-by-step explanation:

3 0

3 years ago