When solving system equations, we can use substitution method or elimination. Today I'm using substitution method.
First name the 2 equations.
3x + y = 3 (1)
x + y = 2 (2)
Now pick one equation and express one algebra in forms of the other.
From (2),
x = 2 - y (3)
Now substitute (3) into (1),
3(2-y) + y = 3
6 - 3y + y = 3
6 - 2y = 3
6 - 3 = 2y
y = 1.5
Now substitute y = 1.5 into (2)
x + 1. 5 = 2
x = 2 - 1.5
x = 0.5
Therefore the answer is x = 0.5 and y = 1.5
bro i think i know the answer but im wrong all the time
Answer:
<h2>You've worked with numbers on a number line. You know how to graph numbers like 0, 1, 2, 3, etc. on the number line. There are other kinds of numbers that can be graphed on the number line, too. Let's see what they look like and where they are located on the number line.</h2>
Step-by-step explanation:
<h2>Hope this helps!!</h2>
