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Tpy6a [65]
3 years ago
15

HELP ASAP!!!!!!!!!!!!!!!

Mathematics
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

I like yo cut gggggggggggg

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What is the amount f rainfall that Miami receives, round to the nearest half or whole? 55 9/10"
Vlad1618 [11]

Answer:

56"

Step-by-step explanation:

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2 years ago
Which number has the same value as 28 tens? 28 or 280
KIM [24]
28 because we are talking about TENS meaning there can only be 2 digits
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what is the answer to the volleyball team at blue point high school has saved $680 and the team plans to spend no more then that
zloy xaker [14]

Answer:

6 x + 23 y  < $ 680  represents the combinations of x balls and y nets that can be purchased.

Step-by-step explanation:

The number of balls than can be purchased  = x

The number of nets than can be purchased  = y

Total savings  = $ 680

Now, the cost of 1 ball =$6

So, the cost of x balls = x ( cost of 1 ball) = x ( $6)  = 6 x

Also, the cost of 1 net =$23

So, the cost of y nets = y ( cost of 1 net = y ( $23)  = 23 y

So, the total amount spent on x balls  and y nets

= Amount spent on x balls + Amount on y nets

=  6 x + 23 y

Also, the saved amount is $680

⇒<u> 6 x + 23 y  < $ 680</u>

Hence, 6 x + 23 y  < $ 680  represents the combinations of x balls and y nets that can be purchased.

4 0
3 years ago
12 + 5 + 32 × 10 − 5 = <br> (12 + 5) + 32 × (10 − 5) =
postnew [5]

Answer:

1. 332

2. 177

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi
inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.        

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

\displaystyle\frac{dr}{dt} = -7\text{ inch per second}

The volume is decreasing at a constant rate.

\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

V = \displaystyle\frac{1}{3}\pi r^2 h

Instant volume =

525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}

Differentiating with respect to t,

\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)

Putting all the values, we get,

\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0
3 years ago
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