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Lana71 [14]
2 years ago
10

Let C be the first quadrant portion of the circle of radius 3 centered on the origin. Find the line itegral for x^2+y^2 over C.

Mathematics
1 answer:
egoroff_w [7]2 years ago
7 0
YX equals +2 squared minus -17 is approximately the answer of the origin
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Trevor tutors French for $12 an hour and scoops ice cream for $8 an hour. He is going to work 20 hours this week. At least how m
PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

Let M = total amount of money earned

M = 12x+8y

To make more than $190, the equation is:

190<12x+8y

Since Trevor is going to scoop ice cream for 20 hours, the equation is:

190<12x+8(20), which simplifies to 190<12x+160.

Isolate x to find the amount of hours that Trevor needs to tutor.

190-160<12x

30<12x

30/12<x

2.5<x

Trevor must tutor for more than 2.5 hours to make more than $190.

4 0
3 years ago
Read 2 more answers
On the beach boardwalk, there were 20 different places
Grace [21]

250 total places to get food this year

7 0
2 years ago
How do you do this problem 1/4 +4x/5=11/20?
Nutka1998 [239]
\frac{1}{4}+\frac{4}{5}x=\frac{11}{20}\\\\\frac{4}{5}x=\frac{11}{20}-\frac{1}{4}\\\\\frac{4}{5}x=\frac{11}{20}-\frac{5}{20}\\\\\frac{4}{5}x=\frac{6}{20}\ \ \ \ \ \ \ |\cdot\frac{5}{4}\\\\x=\frac{30}{80}=\frac{3}{8}
8 0
2 years ago
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is
marysya [2.9K]

Answer:

(a) 0.14%

(b) 2.28%

(c) 48%

(d) 68%

(e) 34%

(f) 50%

Step-by-step explanation:

Let <em>X</em> be a random variable representing the prices paid for a particular model of HD television.

It is provided that <em>X</em> follows a normal distribution with mean, <em>μ</em> = $1600 and standard deviation, <em>σ</em> = $100.

(a)

Compute the probability of buyers who paid more than $1900 as follows:

P(X>1900)=P(\frac{X-\mu}{\sigma}>\frac{1900-1600}{100})

                   =P(Z>3)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid more than $1900 is 0.14%.

(b)

Compute the probability of buyers who paid less than $1400 as follows:

P(X

                   =P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid less than $1400 is 2.28%.

(c)

Compute the probability of buyers who paid between $1400 and $1600 as follows:

P(1400

                              =P(-2

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1400 and $1600 is 48%.

(d)

Compute the probability of buyers who paid between $1500 and $1700 as follows:

P(1500

                              =P(-1

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1500 and $1700 is 68%.

(e)

Compute the probability of buyers who paid between $1600 and $1700 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1700 is 34%.

(f)

Compute the probability of buyers who paid between $1600 and $1900 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1900 is 50%.

8 0
2 years ago
Anser number 6 for me so i kan get a better grade
Arlecino [84]

Answer:

Rita is left with approximately \$ 4

Step-by-step explanation:

Given:

Price for trousers= \$ 19.39

Price for shirt = \$ 27.88

Price for headscarf = \$ 8.62

Total Money she Spent = Price for trousers + Price for shirt + Price for headscarf = \$ 19.39 + \$ 27.88+ \$ 8.62 = \$55.89

Total Money she had before = \$60

∴Total Money left = Total Money she had - Total Money she spent = \$60 - \$55.89 = \$4.11

Rounding to nearest whole number ≈ \$4

7 0
3 years ago
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