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kari74 [83]
3 years ago
13

5x^3+9x^2+6x+1 times the polynomial x?

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0

Answer:

(5x^{4} + 9x^{3} + 6x^{2}  + 1x)

Step-by-step explanation:

(5x^{3} + 9x^{2} + 6x + 1) * x

Multiplying the term by x, adds 1 to the power.

EG

5x^{3} * x = 5x^{3+1} = 5x^{4}

Therefore

(5x^{3} + 9x^{2} + 6x + 1) * =\\(5x^{4} + 9x^{3} + 6x^{2}  + 1x)

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Suppose Ken has 25 coins and nickels and dimes only and has a total of a $1.65 how many of each coin does he have?
nikklg [1K]
x-\ number\ of\ nickels\\
y-\ number\ of\ dimes\\\\
x+y=25 \ \ \ | x=25-y\\
0.05x+0.1y=1.65\\\\
0.05(25-y)+0.1y=1.65\\\\
1.25-0.05y+0.1y=1.65\\\\
1.25+0.05y=1.65\ \ \ | subtract\ 1.25\\\\
0.05y=0.4\ \ \ \ \ | divide\ by\ 0.05\\\\
y=8\\\\
x=25-8=17\\\\
There\ are\ 17 \ nickels\ and\ 8\ dimes.

6 0
3 years ago
Indicate whether the measures 4.35, 5.8, and 7.25 can me the side lengths of a triangle. If they can classify the triangle as ei
Assoli18 [71]

Answer:

Obtuse

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
work for a publishing company. The company wants to send two employees to a statistics conference. To be​ fair, the company deci
NISA [10]

Answer:

Step-by-step explanation:

Here is the complete question.

Dominique, Marco, Roberto , and John work for a publishing company. The company wants to send two employees to a statistics conference. To be fair, the company decides that the two individuals who get to attend will have their names drawn from a hat. This is like obtaining a simple random sample of size 2. (a) Determine the sample space of the experiment. That is, list all possible simple random samples of size n = 2. (b) What is the probability that Dominique and Marco attend the conference? (c) What is the probability that John attends the conference?  ​(d) What is the probability that John stays​ home?

Since there are four employees to select the two to send from. then for us to get the sample space for the experiment we need to merge all possible two employees and represent them as set.

Let D = Dominique, M = Marco, R = Roberto and J = John

a) The sample space for the experiment is the total number of possible outcomes that we can have. It is as given below

S = 4C2 = 4!/(4-2)!2! (Selecting 2 out of 4 employees)

Total sample space = 4!/2!2!

Total sample space = 4*3*2!/2!2

Total sample space = 12/2 = 6

The sample space are S = {DM, DR, DJ, MR, MJ, RJ}

b) Probability is the ratio of number of event to the sample space.

P = n(E)/n(S)

Given n(S) = 6

n(E) is the event of Dominique and Marco attending the conference.

E = {DM}

n(E) = 1

P(D and M) = 1/6

Hence  the probability that Dominique and Marco attend the conference is 1/6

c) For John to attend the conference, the event outcome will be given as;

E = {DJ, MJ, RJ}

n(E) = 3

n(S) = 6

Probability for John to attend the conference is 3/6 = 1/2

d) Probability that John stays at home = 1 - Prob (John attends the conference)

Probability that John stays at home = 1 - 1/2

Probability that John stays at home = 1/2

7 0
3 years ago
Evaluate x=-3, y=4, z=-5<br> Answers suggested below<br> -17<br> 41<br> 23<br> -40<br> -58<br> -16
tatiyna

Answer:

2. -16

6. 23

7. -40

8. -17

9. 41

10. -58

6 0
2 years ago
The domain of ​(f​g)(x) consists of the numbers x that are in the domains of both f and g.
Dovator [93]

The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.

Domain is the values of x in the function represented by y=f(x), for which y exists.

THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".

Now we assume the g(x)=x+2 and f(x)=\frac{1}{x-6}

So here since g(x) is a polynomial function so it exists for all real x.

f(x)=\frac{1}{x-6}<em>  </em>does not exists when x=6, so the domain of f(x) is given by all real x except 6.

Now,

(fg)(x)=f(g(x))=f(x+2)=\frac{1}{(x+2)-6}=\frac{1}{x-4}

So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.

But domain of both f(x) and g(x) consists of the value x=4.

Hence the statement is not TRUE universarily.

Thus the given statement about the composition of function is FALSE.

Learn more about Domain here -

brainly.com/question/2264373

#SPJ10

3 0
1 year ago
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