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3 years ago

5x^3+9x^2+6x+1 times the polynomial x?

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

6 0

Answer:

$(5x^{4} + 9x^{3} + 6x^{2} + 1x)$

Step-by-step explanation:

$(5x^{3} + 9x^{2} + 6x + 1) * x$

Multiplying the term by x, adds 1 to the power.

$5x^{3} * x = 5x^{3+1} = 5x^{4}$

Therefore

$(5x^{3} + 9x^{2} + 6x + 1) * =\\(5x^{4} + 9x^{3} + 6x^{2} + 1x)$

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2 years ago

Read 2 more answers

The temperature changes from 9°F to -5°F. Which of the following expressions model the distance on thermometer between 9°F and -

scoray [572]

Answer:

$d = |- 5- 9|$

Step-by-step explanation:

Given

$Initial = 9^\circ F$

$Final = -5^\circ F$

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3 years ago

What is the value of x? enter your answer into the box.

poizon [28]

Answer:

x = 27

Step-by-step explanation:

ΔBRD and ΔQCD are similar, hence the ratios of corresponding sides are equal, that is

$\frac{BD}{QD}$ = $\frac{RD}{CD}$

note that BD = 26 + 39 = 65

substitute values into the ratio equation

$\frac{65}{39}$ = $\frac{x+18}{x}$ ( cross- multiply )

65x = 39(x + 18)

65x = 39x + 702 ( subtract 39x from both sides )

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3 years ago