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Assoli18 [71]
3 years ago
8

William has a lemonade stand. It costs him $0.30 to make 3 cups of lemonade. Find the rate of change of his cost and respect to

the dozens of cups of lemonade he makes?
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
8 0

Answer:

I'm a bit confused, but it would cost $1.20 to make a dozen cups of lemonade

Step-by-step explanation:

0.30 divided by 3 is 0.10, and a dozen is twelve which makes the problem 0.10x12 which equals $1.20

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Consider the line y=-4/7x+4.
Wittaler [7]

Answer:

1). y = -4/7x         2). y = 7/4x - 65/4

Step-by-step explanation:

1). When a line is parallel, the slope remains the same.

y = -4/7x + b

-4 = -4/7(7) + b

-4 = -4 + b

0 = b

The equation is simply y = -4/7x.

2). When a line is perpendicular, the slope becomes the exact opposite.

y = 7/4x + b

-4 = 7/4(7) + b

-4 = 49/4 + b

-65/4 = b

The equation is y = 7/4x - 65/4.

7 0
2 years ago
Which shows the steps for performing long division in the correct order? will give brainiest if right.
Alex787 [66]

Answer:

Step-by-step explanation:

4

For example long division of 30 by 2 first 2 divided by 3 is 1 put it down then multiply 1 by 2 and subract then just repeat

6 0
3 years ago
Read 2 more answers
Suppose y varies directly as x and y=36 when x=4 find y when x=11
yarga [219]
It equals 99. 4 times 9 equals 36. 11 times 9 equals 99.
5 0
3 years ago
A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas
WITCHER [35]

Answer:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

P(A) = 0.8, P(B) = 0.2

We are assuming that the two events are independent so then we have the following propert:

P(A \cap B ) = P(A) * P(B)

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

P(B' \cup A')

And using the De Morgan laws we know that:

(A \cap B)' = A' \cup B'

So then we can write the probability like this:

P(B' \cup A') = P((A \cap B)')

And using the complement rule we can do this:

P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)

Since A and B are independent we have:

P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32

And then our final answer would be:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

5 0
3 years ago
At Friday's football game, 1,294 tickets were sold for a total amount of $8,816.00. If each student ticket costs $5.00, and each
NeTakaya

Answer:

512 student tickets.

Step-by-step explanation:

Let x be number of student tickets and y be number of adult tickets.

We have been given that at Friday's football game 1,294 tickets were sold. We can represent this information as:

x+y=1294...(1)

We are also told that each student ticket costs $5.00, and each adult ticket costs $8.00 and 1,294 tickets were sold for a total amount of $8,816. We can represent this information as:

5x+8y=8,816...(2)

From equation (1) we will get,

y=1294-x

Substituting this value in equation (2) we will get,

5x+8(1294-x)=8,816

5x+10352-8x=8,816

-3x+10352=8,816

-3x=8,816-10352

-3x=-1536

x=\frac{-1536}{-3}

x=512

Therefore, 512 student tickets were purchased at Fridays football game.

6 0
3 years ago
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