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katen-ka-za [31]
3 years ago
8

Please help me, I need the answer in the next 5mins. AND NO LINKS!!!!!!!

Mathematics
1 answer:
viktelen [127]3 years ago
6 0
The table shows a constant of proportionality the equation would be x*2=y
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Write a linear equation. Explain it in number please! 20 points!!!
juin [17]

To find a linear question, we must have two points on the line and we must know the slope.

Let us choose two points at random:

    (-6,12)    and    (-5,14)

Now let us find the slope of the linear line:

 m = \frac{y2-y1}{x2-x1} =\frac{14-12}{-5--6}  = 2

   So the slope is 2.

Now let us set up the equation which now requires only one point and the slope

      let us use the point (-6,12) and the slope of 2

      y-12 = 2(x+6)\\y = 2x +12 +12\\y= 2x +4

So the linear line is y = 2x + 4.

Hope that helps!

8 0
2 years ago
Find the slope of the line 25 POINTS WILL MARK BRANLIST
UNO [17]

Answer:

-7/4

Step-by-step explanation:

6 0
3 years ago
Write the equation for each translation of the graph of y=| 1/2x-2|+3
Dafna11 [192]
Minimum is (4,3) and Vertical intercept is (0,5) correct me if I’m wrong
5 0
2 years ago
If -xy – 5+ y^2+ x^2= 0 and it is known that dy/dx= y-2x/-x+2y, find all
sleet_krkn [62]

Answer:

There is no point of the form (-1, y) on the curve where the tangent is horizontal

Step-by-step explanation:

Notice that when x = - 1. then dy/dx becomes:

dy/dx= (y+2) / (2y+1)

therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:

0 = ( y + 2) / (2 y + 1)

And we obtain y = -2 as the answer.

But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:

(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2  (instead of zero)

Then, we conclude that there is no horizontal tangent to the curve for x = -1.

3 0
3 years ago
Help solve this equation
Lemur [1.5K]

Answer:

x=1

You solve for x by cross multyplying

6 0
3 years ago
Read 2 more answers
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