To find a linear question, we must have two points on the line and we must know the slope.
Let us choose two points at random:
(-6,12) and (-5,14)
Now let us find the slope of the linear line:
So the slope is 2.
Now let us set up the equation which now requires only one point and the slope
let us use the point (-6,12) and the slope of 2
So the linear line is y = 2x + 4.
Hope that helps!
Answer:
-7/4
Step-by-step explanation:
Minimum is (4,3) and Vertical intercept is (0,5) correct me if I’m wrong
Answer:
There is no point of the form (-1, y) on the curve where the tangent is horizontal
Step-by-step explanation:
Notice that when x = - 1. then dy/dx becomes:
dy/dx= (y+2) / (2y+1)
therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:
0 = ( y + 2) / (2 y + 1)
And we obtain y = -2 as the answer.
But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:
(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2 (instead of zero)
Then, we conclude that there is no horizontal tangent to the curve for x = -1.
Answer:
x=1
You solve for x by cross multyplying
