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Masteriza [31]
3 years ago
11

Solve each system of equations; nonlinear algebra 2 x2 + x + y - 26 = 0 x + y = 1

Mathematics
1 answer:
BigorU [14]3 years ago
8 0

Answer:

(5,-4) and (-5,6)

Step-by-step explanation:

Given:

\left\{\begin{array}{l}x^2+x+y-26=0\\ \\x+y=1\end{array}\right.

Solve it. First, express y in terms of x from the second equation:

y=1-x

Substitute it into the first equation:

x^2+x+1-x-26=0\\ \\x^2-25=0\\ \\(x-5)(x+5)=0

Apply zero product property:

x-5=0\ \text{or}\ x+5=0

So,

x=5\ \text{or}\ x=-5

When x=5, then y=1-5=-4

When x=-5, then y=1-(-5)=6

We get two solutions: (5,-4) and (-5,6)

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